I have a list of integers:
lists = [8,7,2]
I want it to be:
result = 872
I can do it in the following way:
result = 0
for count, i in enumerate(reversed(lists)):
result += i*(10**count)
It works. but I think there should be another better and faster way. Thanks in advance
you can try this
int("".join(list(map(str,lists))))
map all the integers to strings then join them and conver them back to integer.
int("".join(map (str, lists)))You can also do
from functools import reduce
reduce(lambda x,y: 10*x+y, (lists))
No need to convert to string and back.
(for the completeness sake) When list might contain numbers bigger than 9 you can do something more complicated but faster than converting to strings.
from functools import reduce
def combine(x,y):
temp =y
if (temp==0):
return x*10
while(temp>0):
x*=10
temp//=10
return x + y
reduce(combine,lists)
You could also just skin the string:
lists=[8, 7, 2]
result = int((str(lists)).strip("[]").replace(", ",""))
[1] would not convert to a string then int... has to do with the brackets! I'd vote this answer up a dozen times if I could.Here is another simple way to do it using int, str and list comprehension.
lists = [8,7,2]
result = int("".join([str(l) for l in lists]))
