Issue with firebase database update using Javascript

Question

I am trying to update one field in my firebase db from Javascript. The code that I used is:

var config = {
                apiKey: "xxxxxxxxxxxxxxx",
                authDomain: "yyyyyyyyy",
                databaseURL: "https://yuyuyu.firebaseio.com/",
                projectId: "demo1233xyz",
              };
              firebase.initializeApp(config);
              var database = firebase.database();

              database.ref("-UserTable/-LGDHSJSKSIUSN178").update({ verified: false });

But this creates a new entry in the firebase instead of updating the same record. Please find below a sample screenshot.

Can somebody help me to understand how to update an existing field in the table through Javascript.

I don't understand the contents of your "actual outcome" box. It looks like you have two outcomes listed there. — Doug Stevenson
– Doug Stevenson, Commented Jun 15, 2018 at 19:10
What is happening is, the expected change is saved as a new record and the "verified: false" is not getting updated to "verified: true", instead it is added as a new record. — user3567195
– user3567195, Commented Jun 15, 2018 at 19:11
But you can't have two children under the same node with the same name. That's impossible. You probably constructed the path incorrectly. It might help if you show a screenshot of the console so it's absolutely clear what you're seeing. — Doug Stevenson
– Doug Stevenson, Commented Jun 15, 2018 at 19:21
Hello Doug, I have updated the screenshot with actual image. Somehow, I am not able to get the specific field updated. — user3567195
– user3567195, Commented Jun 15, 2018 at 19:29

Doug Stevenson · Accepted Answer · 2018-06-15 20:23:44Z

1

Something has an incorrect path. One of the keys starts with a dash character, and the other does not. Of course, you need to be using the same key in both places.

answered Jun 15, 2018 at 20:23

Doug Stevenson

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user3567195 · Accepted Answer · 2018-06-16 05:55:45Z

0

The best way to do that is

var query = db.ref("<TABLE_NAME>").orderByChild("<FIELD>").equalTo(<VALUE>);
                 query.once("child_added", function(snapshot) {
                   snapshot.ref.update({ <FIELD>: <VALUE> })
                 });

answered Jun 16, 2018 at 5:55

user3567195

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