byte literal array to string

Question

I am new to Python, I am calling an external service and printing the data which is basically byte literal array.

results = q.sync('([] string 2#.z.d; `a`b)')

print(results)
[(b'2018.06.15', b'a') (b'2018.06.15', b'b')]

To Display it without the b, I am looping through the elements and decoding the elements but it messes up the whole structure.

for x in results:
    for y in x:
        print(y.decode())

2018.06.15
a
2018.06.15
b

Is there a way to covert the full byte literal array to string array (either of the following) or do I need to write a concatenate function to stitch it back?

('2018.06.15', 'a') ('2018.06.15', 'b')  
(2018.06.15,a) (2018.06.15,b)

something like the following (though I want to avoid this approach )

for x in results:
    s=""
    for y in x:
        s+="," +y.decode()
    print(s)

,2018.06.15,a
,2018.06.15,b

luz.arthur · Accepted Answer · 2018-06-15 22:05:52Z

1

Following the previous answer, your command should be as follows: This code will result in a list of tuples.

[tuple(x.decode() for x in item) for item in result]

The following code will return tuples:

for item in result:
     t = ()
     for x in item:
             t = t + (x.decode(),)     
     print(t)

edited Jun 15, 2018 at 22:05

answered Jun 15, 2018 at 21:50

luz.arthur

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2 Comments

nyi Over a year ago

Thanks @luz , is there a way to make it like ('2018.06.15', 'a') ('2018.06.15', 'b')

luz.arthur Over a year ago

You mean not being inside a list? I've edited the answer.

Bubble Bubble Bubble Gut · Accepted Answer · 2018-06-15 21:44:41Z

0

You can do it in one line, which gives you back a list of decoded tuples.

[tuple(i.decode() for i in y) for x in result for y in x]

answered Jun 15, 2018 at 21:44

Bubble Bubble Bubble Gut

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2 Comments

nyi Over a year ago

it throws an error AttributeError: 'int' object has no attribute 'decode'

Barmar Over a year ago

You've got too many nested comprehensions, i is the individual bytes of the byte array.

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