Python: Get date format as a string from datetime64[ns]

Question

I want to determine the date format of an input datetime64[ns] value, and obtain a str.

Example:

input value = 1978-07-06

output value = '%Y-%m-%d'

I've tried this but got stuck:

import dateutil.parser
from datetime import datetime

yourdate = dateutil.parser.parse(input)
datetimeobject = datetime.strptime(yourdate,'%Y-%m-%d  %H:%M:%S')

Any help on this would be appreciated. Note: dateinfer gave me "No module named 'infer' " error

pavan · Accepted Answer · 2018-06-17 09:17:59Z

0

extract the date, from input using regular expression

import dateutil.parser
from datetime import datetime

input = '1978-07-06' # or - 06/07/1978
date_obj = dateutil.parser.parse(input)
date_string = date_obj.strftime('%Y-%m-%d %H:%M:%S')

edited Jun 17, 2018 at 9:17

answered Jun 17, 2018 at 5:50

pavan

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1 Comment

TanviP Over a year ago

I'm looking for the strftime format as the output. Also the input date format could change to something like 06/07/1978. What I want to determine is the format based on any given input value ( 06/07/1978 or 1978-07-06). The datatype of input value is datetime64[ns] and not string

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