converting recursive function to arrow function in javascript

Question

How can i convert following function to arrow function? I am using currying here

function mergeString(str){
   return function(str1){
     if(str1){
        return mergeString(str + ' ' + str1); 
     }
     else
     {
       return str;
     }
   }
}

Why would you want to use an arrow function here? No good reason to use one. — Bergi
– Bergi, Commented Jun 17, 2018 at 9:17
Notice that the term "currying" only applies to functions of fixed arity. For varargs functions it's really hard — Bergi
– Bergi, Commented Jun 17, 2018 at 9:18

Nina Scholz · Accepted Answer · 2018-06-17 08:19:30Z

4

You could chain the function heads and then the function body for all.

const mergeString = str => str1 => str1 ? mergeString(str + ' ' + str1) : str;

console.log(mergeString('a')());
console.log(mergeString('a')('b')('c')());
console.log(mergeString('this')('should')('work')('as')('well')());

answered Jun 17, 2018 at 8:19

Nina Scholz

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2 Comments

Mulan Over a year ago

Very nice, but what about mergeString() // => "" ?

Nina Scholz Over a year ago

that need a different ignature of the function.

Jonas Wilms · Accepted Answer · 2018-06-17 08:30:53Z

1

Actuall this is a good usecase for rest parameters:

 const mergeStrings = (...strings) => strings.join(" ");

Usable as:

mergeString(
  "one",
  "two",
  "three"
)

answered Jun 17, 2018 at 8:30

Jonas Wilms

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1 Comment

Jonas Wilms Over a year ago

@nishant just wanted to show some alternative ways to write this :)

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