var string = "Administration for administering str1234 as an administrator";
I want to get the "str1234" only from the string variable. How do I do this?
Note that the index of substring "str1234" is not always consistent.
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can you please post complete code,where this string sets?TAHA SULTAN TEMURI– TAHA SULTAN TEMURI2018-06-20 08:09:39 +00:00Commented Jun 20, 2018 at 8:09
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Use substring to get the stringmbadeveloper– mbadeveloper2018-06-20 08:10:18 +00:00Commented Jun 20, 2018 at 8:10
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1@mbadeveloper is saying that "index of substring "str1234" is not always consistent"TAHA SULTAN TEMURI– TAHA SULTAN TEMURI2018-06-20 08:10:53 +00:00Commented Jun 20, 2018 at 8:10
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Does the string follow a regular pattern (ie. can you use a regular expression)? By index of substring, do you mean that the end is not always consistent, or the start is not always consistent? (ie. are said strings always in the format "Administration for administering x as an administrator")morganbaz– morganbaz2018-06-20 08:24:59 +00:00Commented Jun 20, 2018 at 8:24
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6 Answers
You can use Regular Expressions to search for patterns in strings.
To search for the pattern str followed by 1-4 numbers you would use the following expression:
\bstr\d{1,4}\b
Explanation of RegExp by regex101.com
\bassert position at a word boundary(^\w|\w$|\W\w|\w\W)
strmatches the charactersstrliterally (case sensitive) .
\d{1,4}matches a digit (equal to[0-9]) .
{1,4}Quantifier — Matches between 1 and 4 times, as many times as possible, giving back as needed (greedy) .
\bassert position at a word boundary(^\w|\w$|\W\w|\w\W)
In JavaScript:
let input = 'Administration for administering str1234 as an administrator';
let match = input.match(/\bstr\d{1,4}\b/);
The object match can be used like this:
match[0] // "str1234"
match.index // 33
match.input // "Administration for administering str1234 as an administrator"
3 Comments
Roger
Thanks @dislick. This is almost somehow what I'm looking for. I tested your suggestion and found out that it only matches a word with an 'str' at the beginning using \b. So if I have a case like this: var input = 'Administration for administering costr1234 as an administrator'; Thus, it returned null. Sometimes the word with 'str' from the string does not always begins with 'str' like the one above (costr1234).
Roger
Also, I also have cases like this. var input2 = 'Administration for administering costr1234 and comSTR5242 as an administrator in _STr4324'; I want to get all 'str1234', 'STR5242' and 'STr4324' and store it in an array. I will greatly appreciate your help in doing this!
dislick
Okay @Roger, try this: regex101.com/r/d9Wy3U/1. On the left side there is a "Code Generator" that you can use to see how you would use group matches in JavaScript.
Use indexof()
var string = "Administration for administering str1234 as an administrator";
var index; index= string.indexOf('str1234')
console.log(index)To change 'str1234' to someother value ,you can use replace() .
Hope this helps :)
You can use a regular expression as follows:
var string = "Administration for administering str1234 as an administrator";
var x = string.match(/str[\d]+/)
console.log(x)
Comments
var string = "Administration for administering str1234 as an administrator";
var array = string.split(" ");
cont neededString;
for (const s of array) {
if(s.startsWith('str')){
neededString = s;
break;
}
//or
if(isAlphaNumeric(s))
{
neededString = s;
break;
}
}
public boolean isAlphaNumeric(String s){
String pattern= "^[a-zA-Z0-9]*$";
return s.matches(pattern);
}
1 Comment
user1531038
Snippet throwing error - Uncaught SyntaxError: Unexpected identifier
You can use substr function
var text = "Administration for administering str1234 as an administrator";
var textSearch = "str1234";
console.log(text.substr(text.indexOf(textSearch),textSearch.length));
Comments
You can also do it with indexOf() function by the following snippet:
var string = "Administration for administering str1234 as an administrator";
var subString = "str1234";
if (string.indexOf(subString) >= 0) {
alert(true); //You can add your functionality here.
}