Batch script how to compare array of strings

Question

I have array like a[0]= ABC , a[1]=ABC , a[2]=ABC and I want to compare it using :

if  %a[0]%==%a[1]%=%a[2]% ( echo Equal)

Comparing three is not working but comparing two works fine.

if  %a[0]%==%a[1]% ( echo Equal)

any suggestion, please ?

Where in the help file for the IF command did you read that you could use syntax like that for the IF command? — Squashman
– Squashman, Commented Jul 4, 2018 at 4:39

aschipfl · Accepted Answer · 2018-07-05 09:27:48Z

1

To check multiple (pseudo-)array elements for equality, you could try this:

setlocal EnableDelayedExpansion
set "FLAG=#"   & rem // (flag that is going to be cleared in case of an encountered inequality)
set /A "MAX=9" & rem // (greatest array index number to be included in the comparison loop)
for /L %%I in (1,1,%MAX%) do if not "!a[0]!"=="!a[%%I]!" set "FLAG="
if defined FLAG echo All array elements from index 0 to %MAX% are equal.
endlocal

edited Jul 5, 2018 at 9:27

answered Jul 4, 2018 at 12:21

aschipfl

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Squashman · Accepted Answer · 2018-07-05 01:22:55Z

0

A simple nested IF command will do what you want.

if  "%a[0]%"=="%a[1]%" if "%a[1]%"=="%a[2]%" echo Equal

Another simple solution for comparing 3 numbers to see if they are all the same.

if "%a[1]%,%a[2]%,%a[3]%"=="%a[2]%,%a[3]%,%a[1]%" echo All same

edited Jul 5, 2018 at 1:22

answered Jul 4, 2018 at 4:42

Squashman

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2 Comments

xboxhelp Over a year ago

Hey this works.. but if I have a arry of 10 strings.. How can I compare them via for loop?

aschipfl Over a year ago

@ty139, what about extending that command line accordingly...?

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