PHP remove specific character and number from beginning of string

Question

I want to remove brackets and number from beginning of string but problem is brackets and number is coming only specific string not all.

for example following is my string.

1) [4] Mustangs 8u
2) Pool a First Place
3) Team slect
4) [3] In pruduct

so above you can see only 1 and 4 string have number with brackets at beginning of string so i want to only remove that if that found in string.

I write following code but is not work.

<?php

foreach ($grouped as $round_number => $group) {

        $team_1_name = $group->team_1_name;
        $new_str = preg_replace('/^([0-9]* \w+ )?(.*)$/', '$2', $team_1_name);

        $date = date ('F d, Y g:iA', $unix_time);

    }

?>

You mean string [4] Mustangs 8u must be Mustangs 8u after code? — Deepak Dholiyan
– Deepak Dholiyan, Commented Jul 5, 2018 at 6:30
Yes, also sting ' [3] In pruduct' there are many sting in loop but i found some with number and brackets so i only remove those stings in loop. — Samir Sheikh
– Samir Sheikh, Commented Jul 5, 2018 at 6:31

Lovepreet Singh · Accepted Answer · 2018-07-05 06:32:15Z

3

Try regular expression /^(\[[0-9]\]?\s?)/ as:

$new_str = preg_replace('/^(\[[0-9]\]?\s?)/', '$2', $team_1_name);

For reference: regexr

answered Jul 5, 2018 at 6:32

Lovepreet Singh

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Nigel Ren · Accepted Answer · 2018-07-05 06:46:19Z

2

In case your numbers are multi digit (i.e. '[11] In pruduct')...

echo preg_replace('/^(\[\d*\]?\s?)/', '$2', $team_1_name);

answered Jul 5, 2018 at 6:46

Nigel Ren

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mgutt · Accepted Answer · 2019-08-12 18:38:31Z

0

Instead regex you can use ltrim() with a character mask. If your strings never start with a number:

$new_str = ltrim($team_1_name, "0123456789[] ");

else you could check if the first char is a bracket:

$new_str = $team_1_name[0] == '[' ? ltrim($team_1_name, '0123456789[] ') : '';

answered Aug 12, 2019 at 18:38

mgutt

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