Conditional sorting in Python

Question

In Python how can i sort a two item list based on the condition: if first items are not equal do a normal sort (based on the values of first items), and if the first items are equal sort base on the biggness of second items (the bigger value comes first):

Keys of a dictonary like this:

{(0, 3): (3, 8), (0, 11): (4, 4), (1, 4): (5, 32)}

should be then sorted as such:

[(0, 11), (0, 3), (1, 4)]

Possible duplicate of How do I sort this list of tuples by both values? — Joel
– Joel, Commented Jul 5, 2018 at 13:57

DeepSpace · Accepted Answer · 2018-07-05 13:35:30Z

3

Use a key function that reverses the sorting of the second elements:

d = {(0, 3): (3, 8), (0, 11): (4, 4), (1, 4): (5, 32)}
print(sorted(d.keys(), key=lambda tup: (tup[0], -tup[1])))  # note the minus
# [(0, 11), (0, 3), (1, 4)]

answered Jul 5, 2018 at 13:35

DeepSpace

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2 Comments

Jean-François Fabre Over a year ago

or sorted(d, ... looks like a duplicate to me once the dictionary part is removed

Jean-François Fabre Over a year ago

here: stackoverflow.com/a/49752932/6451573, that said, the answer solves it, but the question is indeed different.

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