delete from an array

Question

I have an array of objects:

$obj = array();

// add the new items
$row = new stdClass();
$row->first = $first;
$row->last = $last;
$row->phone = $phone;

$obj[] = $row;

Now, if I only have the value of $last, is there a way to delete the entire $row object without specifying each key/value? (If it helps to understand, if it was a mysql statement it would be something like "DELETE * FROM $obj WHERE $row->last = 'Thomas' ")

thx

i just threw that in...if it doesn't help clarify then ignore it — user_78361084
– user_78361084, Commented Feb 26, 2011 at 0:42

ThiefMaster · Accepted Answer · 2011-02-26 00:33:57Z

2

Is unset($row); what you want? But there is no need to do that if you are just doing it to save memory...

answered Feb 26, 2011 at 0:33

ThiefMaster

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2 Comments

Russell Dias Over a year ago

unset() does not immediately free memory. Memory, in PHP, gets freed when the garbage collector deems appropriate.

Lightness Races in Orbit Over a year ago

I think that this will not unset the array element, merely the original object. Although physically they may, for a while, be the same object in memory (hurray for copy-on-write) at this point they are semantically separate.

Lightness Races in Orbit · Accepted Answer · 2011-02-26 00:50:29Z

1

You need to know the key. However, if you iterate through the array you can find it.

/* Your original code: */
$obj = array();

// add the new items
$row = new stdClass();
$row->first = $first;
$row->last = $last;
$row->phone = $phone;

$obj[] = $row;

/* My addition: */
$theOneToDelete = $last;
foreach ($obj as $key => $row) {
   if ($row->last == $theOneToDelete) {
      unset($obj[$key]);
      break;
   }
}

There may be a terser approach with some of the array_* functions, but this lays it out.

answered Feb 26, 2011 at 0:50

Lightness Races in Orbit

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Comments

Luciano Costa · Accepted Answer · 2011-02-26 10:30:27Z

1

foreach ($obj as $key => $value) {
  if($obj[$key]->last == $last){
    unset($obj[$key]);
  }
}

Oops, I forgot to format my response as code. I'm new here! =P

edited Feb 26, 2011 at 10:30

answered Feb 26, 2011 at 0:53

Luciano Costa

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