Loop over array of objects in PHP

Question

I am creating an array of objects in jQuery.

var selected_tests = $("#selected_tests").find("tr");
jsonLab = [];
$.each(selected_tests, function() {
  jsonLab.push({
    test: ($(this).children()).eq(0).text(),
    amount: ($(this).children()).eq(1).text()
  });
});

I am posting this array to a PHP file by

$('<input type="hidden" name="jsonLab"/>').val(jsonLab).appendTo('#bill_print');
$("#bill_print").submit();

In my PHP file

if(isset($_POST['jsonLab']))
{
  $lab = json_decode($_POST['jsonLab'],true);
  foreach ($lab as $key => $value) {
    echo $value["test"] . ", " . $value["amount"] . "<br>";
  }   
}

There seems to be some mistake in the way I am using foreach or maybe it's incorrectly formatted JSON which isn't being decoded by PHP. I dont want to use AJAX for the submission.

Have you done any logging to see what $_POST['jsonLab'] is or what your $value are? — Taplar
– Taplar, Commented Jul 10, 2018 at 14:48
Try stringifying your array before setting it to the hidden field. — TiiJ7
– TiiJ7, Commented Jul 10, 2018 at 14:50

Rory McCrossan · Accepted Answer · 2018-07-10 14:53:06Z

3

The issue is with this call:

.val(jsonLab)

jsonLab is an array of objects held in JS. As such, setting it to the val() of a jQuery object will mean toString() is called on it. The result of that is [object Object]. This is what's sent to your PHP logic, hence the error.

To fix this you need to manually stringify the JSON when you set it to the value of the text field:

$('<input type="hidden" name="jsonLab" />').val(JSON.stringify(jsonLab)).appendTo('#bill_print');

Also note that you can use a single map() call on the #selected_tests tr elements instead of selecting then pushing to an explicitly instantiated array:

var jsonLab = $("#selected_tests tr").map(function() {
  return {
    test: $(this).children().eq(0).text(),
    amount: $(this).children().eq(1).text()
  };
}).get();

answered Jul 10, 2018 at 14:53

Rory McCrossan

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2 Comments

sai Over a year ago

Thanks mate , JSON.stringify solved it , i will take your map suggestion aswell

Rory McCrossan Over a year ago

No problem glad to help.

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