Adding multiple items to an array with separations

Question

I have a tableView with cells of products, and when a cell is selected I want the name of the cell to be added to another array and be separated with "" and ,

The array for the tableView is "a", "b", "c" etc..

var name = ""
var arrayOfNames = ""

tableView

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
  tableView.deselectRow(at: indexPath, animated: true)
  name = sections[indexPath.section].productName[indexPath.row]
  arrayOfNames += name
  print(arrayOfNames)
}

So when the cell is pressed it's printing "abc" whereas I want "a", "b", "c"

farkasseb · Accepted Answer · 2018-07-10 16:22:23Z

2

You could store the names in an actual array not a string and then use the plain and simple Swift print(_:separator:terminator:)

var array = ["a", "b", "c"]
print(array)
print(array, separator: ", ")

answered Jul 10, 2018 at 16:22

farkasseb

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1 Comment

Sulthan Over a year ago

or array.joined(separator: ", ") which is more generic

gcourtet · Accepted Answer · 2018-07-10 16:38:11Z

0

The problem might be that you’re simply changing the string arrayOfNames by adding each name to it. Therefore, there is no ” nor , being added. You may want to try:

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
  tableView.deselectRow(at: indexPath, animated: true)
  name = sections[indexPath.section].productName[indexPath.row]
  if(arrayOfNames == “”) {
nameToAdd = “\”“+ name + “\””
  arrayOfNames += name
} else {
nameToAdd = “, \”“+ name + “\””
  arrayOfNames += nameToAdd
}
  print(arrayOfNames)
}

As you can see there, we are first building a string that contains the name between quotes (and the comma) and then only add it to the final string.

edited Jul 10, 2018 at 16:38

answered Jul 10, 2018 at 16:18

gcourtet

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2 Comments

Ivan Over a year ago

Hi GCourtet, Please add some meaningful explanation along with your code so that the original poster can better understand how your answer solves her/his problem. Thank you.

gcourtet Over a year ago

@Ivan Just did, thanks for letting me know that my answer lacked explanations.

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