Find multiple regex in an array

Question

I have an an array containing various timeslots :

var timeArray = ["00:05 - 02:50", "03:05 - 05:50", "05:10 - 07:55", "06:25 - 09:10", "07:55 - 10:40", "09:00 - 11:45", "15:10 - 17:55", "17:05 - 19:45", "18:50 - 21:35", "19:40 - 22:25", "20:45 - 23:40", "22:00 - 00:45", "22:40 - 01:25", "11:55 - 16:15"]

I want to search all the timeslots between 06-12 and push them in an array. I wrote below js but this is returning me an empty array:

var resultArray = new Array();
for (var i = 0; i < timeArray.length; i++) {
    var bar = /^06:^07:^08:^09:^10:^11/;
    if (bar.test(timeArray[i])) {
        alert("found desired timeslots");
        resultArray.push(timeArray[i]);
    }
};

Did you mean to match the first two digits? /^(?:0[6-9]|1[01])/? — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 13, 2018 at 6:43
FWIW, ^06:^07:^08:^09:^10:^11 matches a string starting with "06:^07:^08:^09:^10:^11" (like literally); regular expressions follow rules, use a guide/reference and follow guided practice to increase productivity - because there an infinite set of invalid patterns :} — user2864740
– user2864740, Commented Jul 13, 2018 at 6:45

Nina Scholz · Accepted Answer · 2018-07-13 06:47:40Z

3

You could takes some groups for the wanted times and use only one start indicator.

var timeArray = ["00:05 - 02:50", "03:05 - 05:50", "05:10 - 07:55", "06:25 - 09:10", "07:55 - 10:40", "09:00 - 11:45", "15:10 - 17:55", "17:05 - 19:45", "18:50 - 21:35", "19:40 - 22:25", "20:45 - 23:40", "22:00 - 00:45", "22:40 - 01:25", "11:55 - 16:15"],
    resultArray = timeArray.filter(s => /^(0[6-9]|1(0|1))/.test(s));

console.log(resultArray);

answered Jul 13, 2018 at 6:47

Nina Scholz

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Comments

gil.fernandes · Accepted Answer · 2018-07-13 06:59:46Z

1

The regular expression should rather be: ^06|^07|^08|^09|^10|^11. Another more concise alternative would be: /^0[6-9]|^1[01]/

Runnable example below:

var timeArray = ["00:05 - 02:50", "03:05 - 05:50", "05:10 - 07:55", "06:25 - 09:10", "07:55 - 10:40", "09:00 - 11:45", "15:10 - 17:55", "17:05 - 19:45", "18:50 - 21:35", "19:40 - 22:25", "20:45 - 23:40", "22:00 - 00:45", "22:40 - 01:25", "11:55 - 16:15"]

var resultArray = new Array();
for (var i = 0; i < timeArray.length; i++) {
  var bar = /^06|^07|^08|^09|^10|^11/;
  if (bar.test(timeArray[i])) {
    console.log("found desired timeslots: " + timeArray[i]);
    resultArray.push(timeArray[i]);
  }
};

edited Jul 13, 2018 at 6:59

answered Jul 13, 2018 at 6:45

gil.fernandes

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2 Comments

Wiktor Stribiżew Over a year ago

If you repeat the start of string anchor, you do not need a grouping construct here. var bar = /^06|^07|^08|^09|^10|^11/; will do.

gil.fernandes Over a year ago

@WiktorStribiżew yes, you are right. I have updated the answer.

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