GoLang Array Index on Struct

Question

package main

import "fmt"

type Bar struct {
    high float64
    low  float64
}

func main() {
    var bars = []Bar{}
    bars = []Bar{
        {1.0, 2.0},
        {1.1, 2.1},
        {1.2, 2.2},
        {1.3, 2.3},
        {1.4, 2.4},
        {1.5, 2.5},
    }
    fmt.Println(bars)
    testFunction(&bars)
}

func testFunction(array *[]Bar) {
    for i := 0; i < 3; i++ {
        fmt.Println(*array[i])
    }
}

https://play.golang.org/p/MZwaFALHfuy

Why can I not access the array row?

invalid operation: array[i] (type *[]Bar does not support indexing)

H4xorPL · Accepted Answer · 2018-07-14 11:56:23Z

7

Change the line in for loop to fmt.Println((*array)[i])

*array[i] would try to dereference [i]

(*array)[i] would derefence the array which is your pointer.

Working example: https://play.golang.org/p/yr6WbtS3Aq_c

edited Jul 14, 2018 at 11:56

answered Jul 13, 2018 at 22:08

H4xorPL

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3 Comments

user10078199 Over a year ago

Array in function is not the row index. How would you get access to the second element in the row since you can not do [i][]i] ?

LanceH Over a year ago

fmt.Println((*array)[i].low) . Those are Bar structs, with values for high and low. While you initialize them in what looks like an array or a slice, they aren't arrays, they are of type Bar.

user10078199 Over a year ago

I was looking at the array like #7 on this post stackoverflow.com/questions/5868927/…

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