My split() is not working when there is a space before or after each line in my variable. The code below should return (123,45,67,89) but instead it returns (1234567,89). The REGEX is the problem, probably, but I don't know how to fix it. Your help will be appreciated. Thank you,
var keywordsArray = "1 2 3 \n4 5\n 6 7\n8 9";
keywordsArray = keywordsArray.replace(/\s\s+/g,' ').split('\n');
alert(keywordsArray);You can use the below approaches.
> var result = keywordsArray.split('\n')
undefined
> result
[ '1 2 3 ', '4 5', ' 6 7', '8 9' ]
>
> result = result.map(s => s.replace(/\s+/g, ''))
[ '123', '45', '67', '89' ]
>
> result.join(',')
'123,45,67,89'
>
> var keywordsArray = "1 2 3 \n4 5\n 6 7\n8 9"
undefined
> keywordsArray
'1 2 3 \n4 5\n 6 7\n8 9'
>
> var result = keywordsArray.split('\n')
undefined
> result
[ '1 2 3 ', '4 5', ' 6 7', '8 9' ]
>
> result = result.map(s => parseInt(s.replace(/\s+/g, '')))
[ 123, 45, 67, 89 ]
>
I made it worked with your string, may be this is the hard way... everything has a plan B
var keywordsArray = "1 2 3 \n4 5\n 6 7\n8 9";
keywordsArray = keywordsArray.split('\n').map(item => item.replace(/\s/g,''));
console.log(keywordsArray.join(','));
Just change the regex pattern. First, remove all white space. After that, replace \n with ,.
var keywordsArray = "1 2 3 \n4 5\n 6 7\n8 9";
keywordsArray = keywordsArray.replace(/ */g,'').replace(/\n/g,',');
console.log(keywordsArray);
For more information about regex, check this link
The only issue with your code is that \s is matching \n as well while replace statement, so instead of \s use space (' ').
Please find your code with just update mentioned above:
var keywordsArray = "1 2 3 \n4 5\n 6 7\n8 9";
keywordsArray = keywordsArray.replace(/ +/g,' ').split('\n');
alert(keywordsArray);Try using the literal space ' ' instead of '\s' since
/\s/g any whitespace character
Check out regex101 the next time you get stuck -- it's really helpful!
