avoid $ sign on php for print array value from json

Question

I have to Simple code retrieve data from json.i got problem with json properties that contains like department$_identifier. 'department$_identifier' properties contains the value.but php count it as a variable.how to escape this.

Here is my code :

foreach ($data as $key => $Attendance) {
        if ($Attendance->department$_identifier == 'Administration') {
           echo $Attendance->department$_identifier;
           echo $Attendance->attendanceDate;
           echo $Attendance->status;
           echo $Attendance->_entityName;
        }
      }

How to solve this

buildok · Accepted Answer · 2018-07-16 08:30:19Z

1

use {} like as

echo $Attendance->{'department$_identifier'};

http://php.net/manual/en/function.json-decode.php

answered Jul 16, 2018 at 8:30

buildok

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2 Comments

RK-Rohan Over a year ago

Thanks a lot,Its Work..Save my time.

user8034901 Over a year ago

@RK-Rohan Feel free to accept it as an answer to your question then, please.

user6419437 · Accepted Answer · 2018-07-16 08:31:45Z

0

Try this

foreach ($data as $key => $Attendance) {
    if ($Attendance["department$_identifier"] == 'Administration') {
        echo $Attendance["department$_identifier"];
        echo $Attendance["attendanceDate"];
        echo $Attendance["status"];
        echo $Attendance["_entityName"];
    }
}

answered Jul 16, 2018 at 8:31

user6419437

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