Nested For Loop Variable Increment

Question

I've got a textbox displaying the sketch edited by the software, with variables being changed dynamically.

https://cdn.discordapp.com/attachments/398780553731506176/468835565304020995/unknown.png

But for the buttons array, I need to use some for loops to write the numbers

The format needs to be like this

byte buttons[NUMROWS][NUMCOLS] = { {0,1,2,3,4,}, {5,6,7,8,9,}, {10,11,12,13,14,},

But all I can manage so far is

byte buttons[NUMROWS][NUMCOLS] = { {0,1,2,3,4,}, {1,2,3,4,5,}, {2,3,4,5,6,},

I need to advance the loop so that the numbers increase. I'm using two nested for loops

        int i;
        for(int x = 0; x < rows; x++) //row
        {
            string buttonbyte = "{";
            for (i = x; i < columns + x; i++) //column
            {
                buttonbyte += i;
                buttonbyte += ",";
            }
            sketch[9 + x] = buttonbyte + "},";
        }

The code is for a program that edits an arduino .ide sketch and uploads it, for ease of use.

Any help would be greatly appreciated!

Cheers, Morgan

I'm not sure, it's for the Keypad library. It requires the use of an two dimensional array. — MorGuux
– MorGuux, Commented Jul 17, 2018 at 18:17

Dan · Accepted Answer · 2018-07-17 18:20:43Z

4

I think your second loop needs to be

for (i = (x * columns); i < ((x + 1) * columns); i++)

This will be 0,1,2,3,4 for the first iteration and 5,6,7,8,9 for the second and so on.

answered Jul 17, 2018 at 18:20

Dan

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1 Comment

Andre Motta Over a year ago

This implies lesser changes than my solution @MorGuux use this

marc_s · Accepted Answer · 2019-06-29 07:23:45Z

0

If the jump is always this you just need to make it so that

 int i;
        for(int x = 0; x < rows; x++) //row
        {
            string buttonbyte = "{";
            for (i = 0; i < columns; i++) //column
            {
                buttonbyte += (i + columns*x); // column + columns * row
                buttonbyte += ",";
            }
            sketch[9 + x] = buttonbyte + "},";
        }

PS: This might not work as i don't have a compiler now and you might need to convert (i + columns*x) to a string

edited Jun 29, 2019 at 7:23

marc_s

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answered Jul 17, 2018 at 18:19

Andre Motta

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4 Comments

MorGuux Over a year ago

Yeah that works, but it's one number too high. The output is like {0,1,2,3,4,}, {6,7,8,9,10,}, {12,13,14,15,16,},

Andre Motta Over a year ago

Make i start from zero everytime.

Dan Over a year ago

You would need to rewrite the second loop for this one to work to not include the X, "for (i = 0; i < columns; i++)" would work if you are building the number with (i + columns * x)

Andre Motta Over a year ago

Yes i just noticed that... my bad. The problem of not having a compiler in hand

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