What you want is impossible.
First, notice that the reverse direction would be easy. The difference is that the items in array2 are printed with a newline after each one, while the items in array1 are printed with nothing after each one, so all you'd need to do is add a \n to the end of each item in array_1.
array_2 = [item+'\n' for item in array_1]
You can't just reverse that. There's obviously nothing like item-'\n'. It every item happened to end with a \n, you could do item[:-1], but most of them don't, and you can't remove a newline that isn't there.
And there's no way to cancel out the newline that print is going to add after the string with an anti-newline. I mean, you could include a terminal control sequence to move the cursor up one line so it kind of looks like it did the same thing, but it's not actually doing the same thing, and that would be ridiculously easy to break (run the code on Windows, redirect the output to a file, …).
You can get pretty close. You never said that you need the elements to be in one-to-one correspondence, so you can just do this:
array_2 = [''.join(array_1)]
Now you've just got one item in array_2, so the fact that it's printing newlines between the items doesn't matter.
But there's still a newline at the end, after all one items. And still no way to get rid of that (since the last item doesn't end in a \n that you can remove).
So, the problem is impossible. (Short of trick-question answers like redefining print to special-case your output or something.)
array_2 = array_1maybe?printwithout the other parameters will force a newline at the end of the printing, you need to properly concatenate the elements ofarray_1into a single string. Visit your favorite tutorial for information on basic string operations.