Call function in Node.js command line

Question

require("dotenv").config();
const Twitter = require("twitter");
const keys = require("./keys");
const T = new Twitter(keys.twitter);    

let params = {
screen_name: "TWITTER_NAME",
count: 20
}

function getTweets() {
T.get("statuses/user_timeline", params, gotTweets);
}

function gotTweets(error, data, response) {
if (error) {
    console.log("ERROR: " + error);
} else {
    let tweetLength = data.length;
    for (i = 0; i < tweetLength; i++) {
        console.log(JSON.stringify(data[i].text + " --- POSTED ON: " + 
data[i].created_at, null, 2))
    }
}
}

I am trying to run the function getTweets() in Node.js. I want to essentially run something like: "node app get-tweets" and have it call getTweets() and return the results to me in the terminal. I understand I could just call the function at the end and run node app, but I want to add other functions in the same module like postTweet().

Barış Uşaklı · Accepted Answer · 2018-07-18 19:28:14Z

3

One way to do it is by using process.argv

function getTweets() {
    console.log('getTweets called');
}

function postTweets() {
    console.log('postTweets called')
}

var functionToCall = process.argv[2];

functionToCall && functionToCall();

You can execute it by node app.js getTweets

The first 2 items in argv will be the path to your node executable and the file you are executing followed by arguments you passed to your app.

edited Jul 18, 2018 at 19:28

answered Jul 18, 2018 at 2:19

Barış Uşaklı

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2 Comments

Tsimnuj Hawj Over a year ago

Can I export the function into another .js file and call it like: node app.js get-tweet.js ?

Barış Uşaklı Over a year ago

Yes, but if it's in another file you might as well just execute that file.

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