Issue with Combine array php [closed]

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I am trying to combine two arrays in one array, i want to get value and need to keep it has a key for second array.

example

Array (
     [CONFIRMATION_NUM] => DBSUUA
      )

**

here my code 
first array

**

Array ( 
    [0] => CONFIRMATION_NUM
    [1] => BOOKING_AGENT
    [2] => CONFIRMATION_NUM 
    [3] => BOOKING_AGENT 
    [4] => CONFIRMATION_NUM 
    [5] => BOOKING_AGENT 
    [6] => CONFIRMATION_NUM 
    [7] => BOOKING_AGENT 
    [8] => CONFIRMATION_NUM 
    [9] => BOOKING_AGENT 
    [10] => CONFIRMATION_NUM 
    [11] => BOOKING_AGENT
    [12] => CONFIRMATION_NUM
 )

second array is

Array (
 [0] => DBSUUA 
 [1] => faras-nmdc 
 [2] => UKAZZQ 
 [3] => yco-lmcy 
 [4] => QVTUTS 
 [5] => sohail-npcc 
 [6] => HGQQEF 
 [7] => masood-muss 
 [8] => HOHCFQ 
 [9] => yco-lmcy 
 [10] => JSDUIT 
 [11] => otacallcentre 
 [12] => LHLHWL
)

I tried with this code in this code $tablecolumnsarray is first array and $tabledatacsvcolumnarray is the second array name

$keys = array_keys($tablecolumnsarray);
                    $final=array();

                    foreach ($tabledatacsvcolumnarray as $v) {
                      $final[]=array_combine($keys,$v);
                    }

                    print_r($final);

Please provide a more detailed example of how your expected output would be. — dmotors
– dmotors, Commented Jul 19, 2018 at 19:12
I got it i tried with other code it works has expected thanks to all — star rock
– star rock, Commented Jul 20, 2018 at 14:01

AbraCadaver · Accepted Answer · 2018-07-19 20:35:21Z

1

Unless there's something that you're not showing, no need to loop:

$final = array_combine($tablecolumnsarray, $tabledatacsvcolumnarray);

If $tabledatacsvcolumnarray is actually multidimensional then:

foreach($tabledatacsvcolumnarray as $values) {
    $final[] = array_combine($tablecolumnsarray, $values);
}

edited Jul 19, 2018 at 20:35

answered Jul 19, 2018 at 18:03

AbraCadaver

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3 Comments

star rock Over a year ago

HI i tried this but it showing like this [code] Array ( [CONFIRMATION_NUM] => CGDSAC [BOOKING_AGENT] => otacallcentre )[/code] only one is showing

AbraCadaver Over a year ago

Then your sample arrays are incorrect. I updated with a guess.

star rock Over a year ago

No array is correct i am getting with that details

Karol Samborski · Accepted Answer · 2018-07-19 20:18:20Z

0

As others have said, it is enough to use: $final = array_combine($tablecolumnsarray, $tabledatacsvcolumnarray); to achieve what you want.

But the reason that you're only getting two keys this way is the first array. Take a look at its values:

Array ( 
    [0] => CONFIRMATION_NUM 
    [1] => BOOKING_AGENT 
    [2] => CONFIRMATION_NUM 
    [3] => BOOKING_AGENT 
    [4] => CONFIRMATION_NUM 
    [5] => BOOKING_AGENT 
    [6] => CONFIRMATION_NUM 
    [7] => BOOKING_AGENT 
    [8] => CONFIRMATION_NUM 
    [9] => BOOKING_AGENT 
   [10] => CONFIRMATION_NUM 
   [11] => BOOKING_AGENT 
   [12] => CONFIRMATION_NUM
)

There cannot be two keys with the same name in the array. But there are only two different values in that array so the final array will contain only two (probably last) elements.

answered Jul 19, 2018 at 20:18

Karol Samborski

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1 Comment

star rock Over a year ago

isn't possible to get all?

Chris J · Accepted Answer · 2018-07-19 18:48:41Z

0

$final = array();
foreach ($tablecolumnarray as $n=>$column) {
  $final[$column][] = $tabledatacsvcolumnarray[$n] ;
}
print_r($final) ;

edited Jul 19, 2018 at 18:48

answered Jul 19, 2018 at 17:58

Chris J

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2 Comments

star rock Over a year ago

HI Chris o tried this but it showing like this <code> Array ( [CONFIRMATION_NUM] => CGDSAC [BOOKING_AGENT] => otacallcentre )</code> only one is showing

Chris J Over a year ago

Edited to add [], creating a sub-array. You need to be clearer in what you're expecting so see.

Joe Horn · Accepted Answer · 2018-07-19 18:53:58Z

0

Try

$final = array();
foreach ($tablecolumnsarray as $k => $column) {
  $final[$column] = $tabledatacsvcolumnarray[$k] ;
}
print_r($final) ;

answered Jul 19, 2018 at 18:53

Joe Horn

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