Python (3.4+) Regex for template extensions

Question

I have the following "sample" content:

{% block some_name %}Some Text{% endblock %} 
Something Else
{% block another_name %}Some Other Content{% endblock %}

And I am trying to regex to find both blocks, first the names, then after that the sections, but am only receiving the first back from my "findall" action:

re.findall(r"\{% block ([^\{%]+?) %\}[\s\S]*\{% endblock %\}", contents)

** assuming variable "contents" is the string at the top.

So i need two searches, or combined if possible, returning me something alike:

list[
    ['some_name', 'another_name'],
    ['{% block some_name %}Some Text{% endblock %}', '{% block another_name %}Some Other Content{% endblock %}']
]

Maybe something like re.findall(r"(\{% block (.+?) %}[\s\S]*?\{% endblock %})", s) will do? — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 21, 2018 at 15:32
Thanks for responding, a dict would always be ok! The answer was given, so no need to respond — Tobias Hagenbeek
– Tobias Hagenbeek, Commented Jul 21, 2018 at 20:10

Wiktor Stribiżew · Accepted Answer · 2018-07-21 16:04:14Z

2

You may use

r'(\{%\s*block\s+(.+?)\s*%}[\s\S]*?\{%\s*endblock\s*(?:\2\s*)?%})'

See the regex demo.

Details

( - start of an outer capturing group #1 (as as to get all the match into the list of tuples returned by re.findall):
- `{%
- \s* - 0+ whitespaces
- block - a block substring
- \s+ - 1+ whitespaces
- (.+?) - 1+ chars other than line break chars (replace with [\s\S] to also match line breaks), as few as possible, captured into Group 2
- \s* - 0+ whitespaces
- %} - % substring
- [\s\S]*? - any 0+ chars as few as possible
- \{% - a {% substring
- \s* - 0+ whitespaces
- endblock - a literal substring
- \s* - 0+ whitespaces
- (?:\2\s*)? - an optional sequence of the Group 2 value and 0+ whitespaces after
- %} - a %} substring
) - end of the outer capturing group #1.

See the Python demo:

import re
rx = r'(\{%\s*block\s+(.+?)\s*%}[\s\S]*?\{%\s*endblock\s*(?:\2\s*)?%})'
s = '{% block some_name %}Some Text{% endblock %} \nSomething Else\n{% block another_name %}Some Other Content{% endblock %}'
print(list(map(list, zip(*re.findall(rx, s))))) # Extracting and transposing the list
# => [['{% block some_name %}Some Text{% endblock %}', '{% block another_name %}Some Other Content{% endblock %}'], ['some_name', 'another_name']]

edited Jul 21, 2018 at 16:04

answered Jul 21, 2018 at 15:42

Wiktor Stribiżew

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2 Comments

Håken Lid Over a year ago

If this is for parsing django / jinja templates, you should probably make sure that the endblock tag can optionally also have a name. {% endblock some_name %} is valid. And there can be arbitrary whitespace (including newlines) inside the {% %}.

Tobias Hagenbeek Over a year ago

i appreciate that, while i also work in those, this is not it, but still very useful! Thanks!

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