Javascript find Array elements within Array of Objects values without a for loop

Question

Is it possible to look for arr elements in arrofobjs without a for loop? Since 'Buddy' is in both arr and arrofobjs, i'd expect found to return true

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },
  { type: 'Cat', name: 'Misty', color: 'Black' },
  { type: 'Dog', name: 'Max', color: 'Black' }, ]
var arr = [ 'Buddy', 'Oscar' ]
var found = Object.values(arrofobjs).some(r=> arr.includes(r)) //returns false, but would return true if arrofobj was an object

I think you want arr.includes(r.name) << you need to look for the name attribute — Mark
– Mark, Commented Jul 23, 2018 at 7:19
I reckon that you should explicitly say "without a for loop", or maybe defining the kind of loop you want to avoid (while, forEach etc), because all answers here (some, includes, find etc...) do use loops internally. After all, if you stop to think, from the machine viewpoint this is impossible to do without looping. — Gerardo Furtado
– Gerardo Furtado, Commented Jul 23, 2018 at 7:27

Mihai Alexandru-Ionut · Accepted Answer · 2018-07-23 07:25:43Z

5

You have to access the name property.

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },
  { type: 'Cat', name: 'Misty', color: 'Black' },
  { type: 'Dog', name: 'Max', color: 'Black' }, ]
var arr = [ 'Buddy', 'Oscar' ]
var found = Object.values(arrofobjs).some(r => arr.includes(r.name))
console.log(found);

Since arrofobjs is an array, you can directly apply the some method by using destructing.

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },
{ type: 'Cat', name: 'Misty', color: 'Black' },
{ type: 'Dog', name: 'Max', color: 'Black' }, ]
var arr = [ 'Buddy', 'Oscar' ]
var found = arrofobjs.some(({name}) => arr.includes(name))
console.log(found);

edited Jul 23, 2018 at 7:25

answered Jul 23, 2018 at 7:19

Mihai Alexandru-Ionut

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1 Comment

Satpal Over a year ago

As arrofobjs is an array, no need to use Object.values()

Nikhil Aggarwal · Accepted Answer · 2018-07-23 07:19:08Z

2

You were almost there. As arrofobjs is an array, you can directly iterate over it.

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },{ type: 'Cat', name: 'Misty', color: 'Black' },{ type: 'Dog', name: 'Max', color: 'Black' }];
var arr = [ 'Buddy', 'Oscar' ];
var found = arrofobjs.some(({name})=> arr.includes(name));
console.log(found);

answered Jul 23, 2018 at 7:19

Nikhil Aggarwal

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Comments

Narendra Jadhav · Accepted Answer · 2018-07-23 07:30:50Z

2

You could also use Array.prototype.find() method of array to find the record in array.

DEMO

var arrofobjs = [ { type: 'Dog', name: 'Buddy', color: 'White' },
  { type: 'Cat', name: 'Misty', color: 'Black' },
  { type: 'Dog', name: 'Max', color: 'Black' }],
  arr = ['Buddy', 'Oscar'];
  
arr.forEach(v=>console.log(arrofobjs.find(({name})=>name==v)||`${v} Not fond`));

.as-console-wrapper {max-height: 100% !important;top: 0;}

edited Jul 23, 2018 at 7:30

answered Jul 23, 2018 at 7:25

Narendra Jadhav

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