I have written following code:
def contalpha(n):
num = 65
for i in range(0, n):
for j in range(0, i+1):
ch = chr(num)
print(ch, end=" ")
num = num +1
print("\r")
n = 7
contalpha(n)
The output is:
A
B C
D E F
G H I J
K L M N O
P Q R S T U
V W X Y Z [ \
but what I want is:
A B C D E
A B C D
A B C
A B
A
How can I make it?
I'd advise against using chr. Ascii can be confusing, instead just use a string of all capital ascii characters (which is a sequence of characters, and can be handily found in the string module).
import string
def contalpha(n):
for i in range(n, 0, -1):
print(*string.ascii_uppercase[:i], sep=' ')
contalpha(5)
outputs:
A B C D E
A B C D
A B C
A B
A
string.ascii_uppercase is more obvious than [chr(i) for i in range(65, 91)]. Basically, don't reinvent the wheel.
You need to reverse the range in order to start from the bigger row range(0, n)[::-1]. Then you need to set num = 65 every time you start a new row for it to always start from A.
There you go:
def contalpha(n):
num = 65
for i in range(0, n)[::-1]:
for j in range(0, i+1):
ch = chr(num)
print(ch, end=" ")
num = num +1
num = 65
print("\r")
n = 7
contalpha(n)
Output
A B C D E F G
A B C D E F
A B C D E
A B C D
A B C
A B
A
Try this:
def contalpha(n):
for i in range(n, 0, -1):
num = 65
for j in range(0, i):
ch = chr(num)
print(ch, end=" ")
num = num +1
print("\r")
n = 7
contalpha(n)
First you need to set num to 65 every outer loop to get alphabets from A again and second you should reverse outer loop range to print from max size to min size.
output:
A B C D E F G
A B C D E F
A B C D E
A B C D
A B C
A B
A