C++: Regex pattern

Question

I got a regex pattern: (~[A-Z]){10,30} (Thanks to KekuSemau). And I need to edit it, so it will skip 1 letter. So it will be like down below.

Input:    CABBYCRDCEBFYGGHQIPJOK 
Output:    A B C D E F G H I J K

Perhaps for that input you could match the first character and capture the second character in a group and replace with a whitespace and the capturing group[A-Z]([A-Z])? — The fourth bird
– The fourth bird, Commented Jul 30, 2018 at 7:16
What's with the ~? Just replace .(.) with ` $1` (space+$1). See it here at regex101. — SamWhan
– SamWhan, Commented Jul 30, 2018 at 9:24

xaxxon · Accepted Answer · 2018-07-30 01:13:33Z

1

Just match two letters each iteration but only capture the second part.

(?:~[A-Z](~[A-Z])){5,15}

I cut the repetition count (the bit inside the {}'s) by half since the new regex is matching two at a time.

The ?: in (?:...) bit disables capturing of the group.

answered Jul 30, 2018 at 1:04

xaxxon

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Comments

Muhammad Ashhar Hasan · Accepted Answer · 2018-07-30 09:16:14Z

0

In regex only, there is no way you can achieve this directly. But you can do this in code:

Use following regex:

(.(?<pick>[A-Z]))+

and in code make a loop on "captures" of desired group, like in c#:

string value = "";
for (int i = 0; i < match.Groups["pick"].Captures.Count; i++)
{
   value = match.Groups["pick"].Captures[0].Value;
}

answered Jul 30, 2018 at 9:10

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