create local variable in calling function, from a string

Question

I want to be able to call a function, that will set one or more local variables in the calling function. For instance:

function someFunc () {
 loadTranslatedStrings($LOCALS, "spanish");
 echo $hello; // prints "hola";
 }

function loadTranslatedStrings (&$callerLocals, $lang) {
 if ($lang == 'spanish')
   $callerLocals['hello'] = 'hola';
 else if ($lang == 'french')
   $callerLocals['hello'] = 'bonjour';
 else
   $callerLocals['hello'] = 'hello';
 }

(I'm guessing it is impossible to do this, but might as well ask...)

alex · Accepted Answer · 2011-03-02 00:44:53Z

5

You could do this...

function someFunc () {
   loadTranslatedStrings($lang, "spanish");
   extract($lang); 
   echo $hello; // prints "hola";
}

CodePad.

answered Mar 2, 2011 at 0:44

alex

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2 Comments

rob Over a year ago

awesome, thanks. When it let's me accept an answer, I'll flip a coin between you and Tim. :)

rob Over a year ago

I gave him an upvote, of course. Thanks to both of you, this solves the problem perfectly.

user142162 · Accepted Answer · 2011-03-02 00:44:55Z

4

The closest I think you could get is by using extract:

function someFunc()
{
   extract(loadStrings('french'));
   echo $hello;
}

function loadStrings($lang)
{
   switch($lang)
   {
      case 'spanish':
         return array('hello' => 'hola');
      case 'french':
         return array('hello' => 'bonjour');
   }
}

answered Mar 2, 2011 at 0:44

user142162

1 Comment

alex Over a year ago

2 seconds! +1 for the same idea as me :)

vissi · Accepted Answer · 2011-03-02 00:45:58Z

0

You can do that using $GLOBALS: $GLOBALS['hello'] = 'hola';

answered Mar 2, 2011 at 0:45

vissi

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1 Comment

alex Over a year ago

That won't be local to the function.

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