Getting IndexError: string index out of range

Question

I'm currently learning python from on Edx 'Python for the absolute beginner. i am to Create a program that inputs a phrase (like a famous quotation) and prints all of the words that start with h-z, i keep getting an error message on line, Here's the code,can someone please help out with a correction.

quote= input("enter a 1 sentence quote, non-alpha separate words:")
word=""
for char in quote:
    if char.isalpha() == True:
        word += char.upper()

    else:
        if word[0].lower() >= "h":
            print(word.upper())
            word=""

        else:
            word=""

Have you used a debugger to see what changes are being made to word? — Scott Hunter
– Scott Hunter, Commented Aug 2, 2018 at 20:01
At the first iteration word is an empty string and does not have word[0]. — DYZ
– DYZ, Commented Aug 2, 2018 at 20:02
Initially, there is no index 0 of word. So if the first character is not alpha, you get this error. — user9455968
– user9455968, Commented Aug 2, 2018 at 20:02

Maurício Borges · Accepted Answer · 2018-08-02 20:07:42Z

1

Probably it is entering on ELSE clause on the first loop. Since word is still empty, there is no word[0].

But I really did not understand what you're exactly trying to do.

answered Aug 2, 2018 at 20:07

Maurício Borges

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Comments

whackamadoodle3000 · Accepted Answer · 2018-08-02 20:14:04Z

0

Try this:

quote=input("enter a 1 sentence quote, non-alpha separate words:")
[print(e) for e in quote.split(" ") if e[0].upper() in "HIJKLMNOPQRSTUVWXYZ"]

answered Aug 2, 2018 at 20:14

whackamadoodle3000

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