Function with multiple parameters in swift

Question

I need to define and call a function called areaOfRectangle that takes two Int parameters, length, and width, and prints the result of length * width. I actually got result with length * width but it is telling me to make sure I’m defining a function with the correct name and parameters. The answer below will print length * width which is right but the steps are not what it should be.

func areaOfRectangle(length: Int, width: Int) {

    print(“length * width”)

}

areaOfRectangle(length: 0, width: 0)

Look under Printing constants and Variables.

Fabian
– Fabian

2018-08-09 05:37:36 +00:00
Commented Aug 9, 2018 at 5:37 — Fabian
– Fabian, Commented Aug 9, 2018 at 5:37

Parth Dhorda · Accepted Answer · 2018-08-09 05:38:00Z

1

You have defined the function correctly but made a small mistake in the front statement as it will always print length * width in the output console as its a string not the operator or operands. Here is the solution

func areaOfRectangle(length: Int, width: Int) {

    print("\(length * width)")

}

areaOfRectangle(length: 0, width: 0)

just added '\'() in the print statement

answered Aug 9, 2018 at 5:38

Parth Dhorda

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Comments

Dharmesh Kheni · Accepted Answer · 2018-08-09 05:40:51Z

1

Here is the way you can return string result from Int parameters:

//define a return type as String here
func areaOfRectangle(length: Int, width: Int) -> String {
    print("\(length * width)")  //same thing you can print here 
    return "\(length * width)"  //return it as String
}

let result = areaOfRectangle(length: 5, width: 5)
print(result) //"25"

edited Aug 9, 2018 at 5:40

answered Aug 9, 2018 at 5:36

Dharmesh Kheni

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2 Comments

Ji. K Over a year ago

I'd like to print "length * width" so the answer is right but the steps are not correct.

Dharmesh Kheni Over a year ago

what you mean by print can you please elaborate?

Rizwan · Accepted Answer · 2018-08-09 06:02:29Z

0

print(“length * width”)

in this statement length and width are being treated as string literals. Any thing that comes between "" is a string literal at least in swift, also in some other languages.

Swift provide a very good syntactic sugar to use variables and constants within the string by putting the vars and lets within \(). Hence when you correct the above statement to print(“\(length * width)”). It will print correct result of length*width.

Updated code:

func areaOfRectangle(length: Int, width: Int) {
    print(“\(length * width)”) //42
}
areaOfRectangle(length: 6, width: 7)

edited Aug 9, 2018 at 6:02

answered Aug 9, 2018 at 5:50

Rizwan

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Comments

Nadia Tariq · Accepted Answer · 2021-12-11 20:04:34Z

-1

Explaination: function with multiple parameters., in which the function greet have parameter of alreadyGreeted also a condition it will check when we give argument label of person and bool is true, we call it, and function will start its execution... condition is checked,. then greetAgain function is called with its argument label... and print "hello Again" with person name that is in greet-main function calling parameter.

answered Dec 11, 2021 at 20:04

Nadia Tariq

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1 Comment

Community Over a year ago

As it’s currently written, your answer is unclear. Please edit to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers in the help center.

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