Given this Object in Javascript
{
"0": "hello",
"1": { text: "world" }
}
What's the shortest way to create this array from that object?
[
"hello",
{ text: "world" }
]
I've seen somebody using Array.prototype.splice(theObject) but it doesn't seem to work for me.
Update:
0 and 1 can be any arbitrary string value and the order at property level needs to be maintained in the corresponding array. Just use Object.values:
console.log(Object.values({
"0": "hello",
"1": { text: "world" }
}));
"hello" will be the first value in the resulting array.
If you want to be sure that the original keys of the object correspond to the positions in the resulting array, you can't rely on Object.values() or a for ... in loop. You can use Object.keys() and sort that array.
var keys = Object.keys(yourObject);
keys.sort();
var array = keys.map(key => yourObject[key]);
Now understand that the call to .sort() can include a comparator function to impose any ordering desired on the original object keys. The sample in the OP is very simple, and the above would work. However more complicated keys might require a custom comparator.
.sort() can explicitly impose any ordering desired. I'll extend the answer.This should maintain the order based on the keys, including where keys have more than one digit
const test = {
"0": "hello",
"3": "three",
"1": { text: "world" },
"2": "two",
"11": "eleven",
}
const transform = obj => Object.keys(obj)
.sort((a, b) => parseInt(a) > parseInt(b) ? 1 : -1)
.map(key => obj[key])
console.dir(transform(test))let src = {
"0": "hello",
"1": {
text: "world"
}
}
let res = [src].map(it => [it['0'], it['1']])
console.log(res)Try using for..in loop like this:
let obj = {
"0": "hello",
"1": { text: "world" }
}
let result = []
for(var value in obj){
result.push(obj[value])
}
