Why do i get "AAAAAAAAA" instead of "1A234A567" from following Code:
String myst = "1.234.567";
String test = myst.replaceAll(".", "A");
System.out.println(test);
Any Idea?
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possible duplicate of Backslash problem with String.replaceAllMcDowell– McDowell2011-05-26 08:42:47 +00:00Commented May 26, 2011 at 8:42
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4 Answers
Try this:
String test = myst.replace(".", "A");
The difference:
replaceAll() interprets the pattern as a regular expression, replace() interprets it as a string literal.
Here's the relevant source code from java.lang.String (indented and commented by me):
public String replaceAll(String regex, String replacement) {
return Pattern.compile(regex)
.matcher(this)
.replaceAll(replacement);
}
public String replace(CharSequence target, CharSequence replacement) {
return Pattern.compile(
target.toString(),
Pattern.LITERAL /* this is the difference */
).matcher(this)
.replaceAll(
Matcher.quoteReplacement(
/* replacement is also a literal,
not a pattern substitution */
replacement.toString()
));
}
Reference:
answered Mar 3, 2011 at 10:28
Sean Patrick Floyd
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Comments
replaceAll function take a regular expression as parameter. And the regular expression "." means "any character". You have to escape it to specify that it is the character you want : replaceAll("\\.", "A")
Comments
You need to escape .
make it
String myst = "1.234.567";
String test = myst.replaceAll("\\.", "A");
System.out.println(test);
Comments
Because every single char of the input matches the regexp pattern (.). To replace dots, use this pattern: \. (or as a Java String: "\\.").
