Replace a substring using bash script [duplicate]

Question

I am trying to replace a substring of a string in a file called db_config using bash.

code in db_config file is

dbname=test_1

I want to replace "test_1" to "production".

The substring can be test_1 or test1 or testing or any random string but the format will be dbname=(whatever the name)

This needs to be changed to dbname=production

I tried both these syntax. Neither worked.

sed -i -e 's/dbname=*/dbname="ihs"/g' db_config

sed -i -e 's/dbname=$/dbname="ihs"/g' db_config

I know how to parse this in python but i cant seem to find a solution in bash.

Thanks in advance!

anubhava · Accepted Answer · 2018-08-13 19:24:04Z

1

You should be using a capture group and .* to match everything after keyname:

sed -i 's/^[[:blank:]]*\(dbname=\).*/\1production/' db_config

answered Aug 13, 2018 at 19:24

anubhava

790k67 gold badges603 silver badges671 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Thanks a lot, anubhava. This worked. Thanks for explaining the solution too.