How to print python Byte variable?

Question

I have this byte variable

testByte = b"\x02\x00\x30\x03\x35"

I would like to print it out

I've tried:

listTestByte = list(testByte)

However, I'm getting

[2, 0, 48, 3, 35]

I'm expecting it to be:

[2, 0, 30, 3, 35]

The 30 in \x30 is a hexadecimal value. int values are printed using their decimal values. What exactly is it you want to do? What would you expect b"\xff" to print as? — Patrick Haugh
– Patrick Haugh, Commented Aug 17, 2018 at 15:52
Also since it's hexadeicmal value you should be getting [2, 0, 48, 3, 53] — sP_
– sP_, Commented Aug 17, 2018 at 15:53

sP_ · Accepted Answer · 2021-03-26 00:30:25Z

10

What you have are hexadecimal values. So what you're getting is what you should be getting. (Except that you should be getting [2, 0, 48, 3, 53] and not [2, 0, 48, 3, 35].)

If you want the list to have what you have in hexadecimal you can try converting it back to hexadecimal.

testByte = b"\x02\x00\x30\x03\x35"
listTestByte = list(testByte)
print(listTestByte)             # [2, 0, 48, 3, 53]
listTestByteAsHex = [int(hex(x).split('x')[-1]) for x in listTestByte]
print(listTestByteAsHex)        # [2, 0, 30, 3, 35]

Or use string operations, to split at '\x' depending on your purpose.

edited Mar 26, 2021 at 0:30

answered Aug 17, 2018 at 16:00

sP_

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2 Comments

user1872384 Over a year ago

Thx. I'm hitting "invalid literal for int () with base 10" for listTestByte with value [2,0,53,3,0,0,0,3,61]. Why is it so?

sP_ Over a year ago

Hexadecimal values range from 0-9 and a-f. And 61 in decimal is 3D in hex. So that doesn't convert to int. So remove int() to get the value as string. If you still need 61 then I'd suggest using string operations.

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