_, _, XYZ, Path, filename = string.find("re32:HKEY_LOCAL_MACHINE\\SOFTWARE\\XYZ\\Assistant\\Active ", "(%w+):(.+)\\(.*)")
print(XYZ)
print(Path)
print(filename)
The above code outputs:
re32
HKEY_LOCAL_MACHINE\SOFTWARE\XYZ\Assistant\
Active
I need the output in below form--that is, instead of three groups, I need four:
re32
HKEY_LOCAL_MACHINE
SOFTWARE\XYZ\Assistant\
Active
What has to be done in this case?
XYZ, RootKey, Path, filename = ([[re32:HKEY_LOCAL_MACHINE\SOFT WARE\XYZ\Assistant\Active ]]):match ( [[(%w+):([^\]+)(.+)\(.*)]])
Use [[]] instead of "" to stop escape sequences.
_, _, XYZ, RootKey, Path, filename = string.find("re32:HKEY_LOCAL_MACHINE\SOFTWARE\XYZ\Assistant\Active ", "(%w+):(.-)\(.+)\(.*)")
print(XYZ)
print(RootKey)
print(Path)
print(filename)
Should produce
re32
HKEY_LOCAL_MACHINE
SOFTWARE\\XYZ\\Assistant\\
Active
You can have named groups in regular expressions. example:- (/group1\[0-9])(abc) (replace "/" with "<" and "\" with ">" in above example) this regx will match "3abc" and you can get the matched number by choosing the group name(group1) in the match. refeer this http://www.regular-expressions.info/named.html
_, _, XYZ, RootKey, Path, filename = string.find(
"re32:HKEY_LOCAL_MACHINE\\SOFTWARE\\XYZ\\Assistant\\Active ",
"(%w+):(.-)\\(.+\\)(.*)")
print(XYZ)
print(RootKey)
print(Path)
print(filename)
output:
re32 HKEY_LOCAL_MACHINE SOFTWARE\XYZ\Assistant\ Active
This answer is essentially the same as Serge's, but the backslashes are properly escaped in the target and pattern strings, and the final backslash is included the third capturing group.
But most importantly, this solution is tested. Ideone FTW!
