Solutions:
Simple:
(this.$refs.form as Vue & { validate: () => boolean }).validate()
Alternative (use this if you reference this.$refs.form multiple times in your component):
computed: {
form(): Vue & { validate: () => boolean } {
return this.$refs.form as Vue & { validate: () => boolean }
}
} // Use it like so: this.form.validate()
Reusable (use this if you use the v-form component multiple times across your application):
// In a TS file
export type VForm = Vue & { validate: () => boolean }
// In component, import `VForm`
computed: {
form(): VForm {
return this.$refs.form as VForm
}
}
Explanation:
In the Vue template syntax, we can use the ref attribute on a Vue instance or a DOM element. If ref is used in a v-for loop, an array of Vue instances or DOM elements is retreived.
This is why this.$refs can either return Vue | Element | Vue[] | Element[].
In order for TypeScript to know which type is being used, we need to cast the value.
We can either do:
(this.$refs.form as Vue).validate() or (<Vue>this.$refs.form).validate()
We cast it to Vue because v-form is a Vue instance (component) and not an Element.
My personal preference is to create a computed property which returns the Vue instance(s) or DOM element(s) already casted.
ie.
computed: {
form(): Vue {
return this.$refs.form as Vue
}
}
The v-form instance has a validate method that returns a boolean, so we need to use an intersection type literal:
computed: {
form(): Vue & { validate: () => boolean } {
return this.$refs.form as Vue & { validate: () => boolean }
}
}
Then we can use it like so: this.form.validate()
A better solution would be to create a type with the intersection so that it can be reused across multiple components.
export type VForm = Vue & { validate: () => boolean }
Then import it in the component:
computed: {
form(): VForm {
return this.$refs.form as VForm
}
}