How to check if a string contains a substring and does not in Bash [duplicate]

Question

I am wanting to use a switch/ case statement in bash to check if a file name which is a string contains something but also does not.

Here is my case:

case "$fileName" in
    *Failed|!cp*)
       echo "match"
     ;;
esac

But this does not work currently, how can I see if the string matches "Failed" but also does not contain "cp"?

It would be great if this could be done in a switch/ case as well

Possible duplicate of Switch case with fallthrough? Also see How to use Shellcheck, How to debug a bash script? (U&L.SE), How to debug a bash script? (SO), How to debug bash script? (AskU), Debugging Bash scripts, etc. — jww
– jww, Commented Aug 31, 2018 at 12:15

Barmar · Accepted Answer · 2018-08-31 10:53:21Z

2

! has to be followed by a parenthesized list of patterns, not the pattern itself.

| in a case is for OR, not AND. To get AND, you should nest cases.

case "$fileName" in
    *Failed)
        case "$fileName" in
            cp*) ;;
            *) echo "match" ;;
        esac
     ;;
esac

Or you could just use if instead of case:

if [[ $filename = *Failed && $filename != cp* ]]
then echo match
fi

answered Aug 31, 2018 at 10:47

Barmar

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2 Comments

What is the 'extglob' option for?

Extended globbing syntax.

bipll · Accepted Answer · 2018-08-31 10:57:56Z

0

Alternatively you can use if and pipes for instance:

if echo 'Failed' | grep -v cp | grep -q Failed ; then
    echo Failed without cp
else
    echo It's either Winned or cp.
fi

answered Aug 31, 2018 at 10:57

bipll

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