filtering out string dates in python list [duplicate]

Question

I have a list that contains dictionaries(my_list) that looks like

[{'name': 'jane', 'number': 123, 'birthday': '04/05/78'}, 
 {'name': 'summer', 'number': 542, 'birthday': '07/01/1990'},
 {'name': 'carter', 'number': 003, 'birthday': '12/15/1992'}]

I am trying to filter out results by a birthday

my_filter = [elf for elf in my_list if 'birthday' >= '01/01/1980']

This should eliminate the first entry but when i print out my filter all three entries are still being printed.

How can i compare the string dates (birthday) to filter out data?

blhsing · Accepted Answer · 2018-09-03 02:41:24Z

2

You can use datetime.strptime to parse the date strings into datetime objects for comparison. Since the year portions of your date strings are inconsistently formatted, you should normalize them first with a regex substitution:

from datetime import datetime
import re
my_list = [{'name': 'jane', 'number': 123, 'birthday': '04/05/78'},
 {'name': 'summer', 'number': 542, 'birthday': '07/01/1990'},
 {'name': 'carter', 'number': 3, 'birthday': '12/15/1992'}]
print([elf for elf in my_list if datetime.strptime(re.sub(r'\d\d(\d\d)$', r'\1', elf['birthday']), '%m/%d/%y') >= datetime(1980, 1, 1)])

This outputs:

[{'name': 'summer', 'number': 542, 'birthday': '07/01/1990'}, {'name': 'carter', 'number': 3, 'birthday': '12/15/1992'}]

answered Sep 3, 2018 at 2:41

blhsing

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