Split string but replace with another string and get list

Question

I am trying to split a string but it should be replaced to another string and return as a list. Its hard to explain so here is an example:

I have string in variable a:

a = "Hello World!"

I want a list such that:

a.split("Hello").replace("Hey") == ["Hey"," World!"]

It means I want to split a string and write another string to that splited element in the list. SO if a is

a = "Hello World! Hello Everybody"

and I use something like a.split("Hello").replace("Hey") , then the output should be:

a = ["Hey"," World! ","Hey"," Everybody"]

How can I achieve this?

This link here to what you do. stackoverflow.com/questions/2582138/… — Wong Siwei
– Wong Siwei, Commented Sep 4, 2018 at 3:30
@EdwardKotarski Its not working with HelloWorld!. I don't have spaces in my original data. These are just examples. — user10312797
– user10312797, Commented Sep 4, 2018 at 3:35
@WongSiwei I don't want loops etc to make my program complex. — user10312797
– user10312797, Commented Sep 4, 2018 at 3:36
You should be more specific where you want to separate the string then. Do you want to separate by space or by the first uppercase character? — mynameisarjay
– mynameisarjay, Commented Sep 4, 2018 at 4:27

Hugo G · Accepted Answer · 2018-09-04 03:53:00Z

1

From your examples it sounds a lot like you want to replace all occurrences of Hello with Hey and then split on spaces.

What you are currently doing can't work, because replace needs two arguments and it's a method of strings, not lists. When you split your string, you get a list.

>>> a = "Hello World!"
>>> a = a.replace("Hello", "Hey")
>>> a
'Hey World!'
>>> a.split(" ")
['Hey', 'World!']

answered Sep 4, 2018 at 3:53

Hugo G

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Melvin · Accepted Answer · 2018-09-04 03:30:41Z

0

x = "HelloWorldHelloYou!" 
y = x.replace("Hello", "\nHey\n").lstrip("\n").split("\n") 
print(y) # ['Hey', 'World', 'Hey', 'You!']

This is a rather brute-force approach, you can replace \n with any character you're not expecting to find in your string (or even something like XXXXX). The lstrip is to remove \n if your string starts with Hello.

Alternatively, there's regex :)

answered Sep 4, 2018 at 3:30

Melvin

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1 Comment

Onyambu Over a year ago

why would someone downvote this answer? It seems to be the best so far. well a bit of modification. try doing x.replace("Hello", "\nHey\n").strip().split() instead. This will split in spaces and line breaks too. Also it will do both stripping on both sides

user10312857 · Accepted Answer · 2018-09-04 03:38:27Z

0

this functions can do it

def replace_split(s, old, new):
    return sum([[blk, new for blk] in s.split(old)], [])[:-1]

answered Sep 4, 2018 at 3:38

user10312857

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1 Comment

Hugo G Over a year ago

Downvoted because this is extremely overcomplicated and doesn't answer the question directly.

mynameisarjay · Accepted Answer · 2018-09-04 04:42:10Z

0

It wasnt clear if you wanted to split by space or by uppercase.

import re    

#Replace all 'Hello' with 'Hey'

a = 'HelloWorldHelloEverybody'
a = a.replace('Hello', 'Hey')

#This will separate the string by uppercase character

re.findall('[A-Z][^A-Z]*', a) #['Hey', 'World' ,'Hey' ,'Everybody']

edited Sep 4, 2018 at 4:42

answered Sep 4, 2018 at 4:34

mynameisarjay

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Comments

user70 · Accepted Answer · 2018-09-04 04:52:16Z

0

You can do this with iteration:

a=a.split(' ')
for word in a:
    if word=='Hello':
      a[a.index(word)]='Hey'

answered Sep 4, 2018 at 4:52

user70

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