Java split function reading space after a character as an empty string

Question

input: he is a good, person.

desired output: {"he","is","a","good","person"}

program output: {"he","is","a","good"," ","person"}

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        String s = scan.nextLine();
        String[] ace = s.trim().split("[\\s+!,?._'@]");
        scan.close();
        System.out.println(ace.length);
        for(String c : ace)
            System.out.println(c);
    }
}

am asking for first time here. need pointers for next time

Is your regex correct?

Richard
– Richard

2018-09-08 18:13:20 +00:00
Commented Sep 8, 2018 at 18:13 — Richard
– Richard, Commented Sep 8, 2018 at 18:13
regex is for any space and these special characters !,?._'@

micro
– micro

2018-09-08 18:14:51 +00:00
Commented Sep 8, 2018 at 18:14 — micro
– micro, Commented Sep 8, 2018 at 18:14

Mureinik · Accepted Answer · 2018-09-08 18:16:08Z

6

You have a sequence of two delimiters between "good" and "person" - a space and a comma. You could tweak your regex to allow multiple consecutive delimiter characters as the same delimiter:

String[] ace = s.trim().split("[\\s+!,?._'@]+");
// Here ------------------------------------^

answered Sep 8, 2018 at 18:16

Mureinik

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2 Comments

micro Over a year ago

thanks. this worked .could you please tell me what that + do in the regex(i am new to programming)

Mureinik Over a year ago

@micro "+" in regex means "one or more" - so instead of the " " and the "," being treated as different delimiters, the entire sequence of ", " is treated as a single delimiter.

Oleg Cherednik · Accepted Answer · 2018-09-08 18:18:15Z

4

You could use RegExp:

String[] words = str.split("\\W+");

This is a Demo

answered Sep 8, 2018 at 18:18

Oleg Cherednik

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