Disable Logger for websockets Package in Python

Question

I am using the websockets package to create a websocket server in python; at the same time I am heavily using the logging in different log-levels.

The websockets documentation mentions the logger configuration and that it could be changed to the log-level ERROR using

     logger = logging.getLogger('websockets.server')
     logger.setLevel(logging.ERROR)
     logger.addHandler(logging.StreamHandler())

This, however, does not have any effect in my code, wherever I place it (below the import, before the websockets import, within __main__). I'd like to have two configurations - one global logging configuration and the logger-configuration of the websockets server.

Another option would be to disable the logging completely for the websockets module but I can't figure out how to do that. Any ideas?

martin · Accepted Answer · 2018-09-11 19:15:53Z

6

It turns out it is not only the websockets.server that is emitting lots of debug messages, there's other ones too. I've ended up hunting down those packages by using the %(name)s field in the root logger configuration and could find websockets.protocol being responsible for the additional messages.

logging.basicConfig(
    level=logging.DEBUG,
    format='%(asctime)s %(name)s %(levelname)-8s  %(message)s',
    datefmt='(%H:%M:%S)')

# disable all loggers from different files
logging.getLogger('asyncio').setLevel(logging.ERROR)
logging.getLogger('asyncio.coroutines').setLevel(logging.ERROR)
logging.getLogger('websockets.server').setLevel(logging.ERROR)
logging.getLogger('websockets.protocol').setLevel(logging.ERROR)

answered Sep 11, 2018 at 19:15

martin

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Chris Zuidema · Accepted Answer · 2019-01-23 11:33:07Z

3

When you start a websocket, set:

websocket.enableTrace(False)

No DEBUG and hart beat messages will be logged or shown in the console.

My example code:

def start_websocket(url, listen_method):
"""
Start a websocket connection.

:param url: string
:param listen_method: method
"""
# Enable or Disable logging
websocket.enableTrace(False)

ws = websocket.WebSocketApp(
    url,
    on_message=listen_method,
    on_error=on_error,
    on_close=on_close
)

ws.on_open = on_open

ws.run_forever(ping_interval=3, ping_timeout=2)

answered Jan 23, 2019 at 11:33

Chris Zuidema

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