How to convert String Array to String in Swift

Question

I need to convert a String array into single String.

This is my array:

["1","2","3","4","5"]

I need to get this:

"["1","2","3","4","5"]"

i saw this question already your link provide answer without array i want array please have a look — Jhony
– Jhony, Commented Sep 12, 2018 at 11:09
Inside the enclosing double quotes, double quotes needs to be escaped. So, your "["1","2","3","4","5"]" cannot be a valid string in any possible use cases. For what do you want the single string? — OOPer
– OOPer, Commented Sep 12, 2018 at 11:24

Rakesha Shastri · Accepted Answer · 2018-09-12 15:39:40Z

4

This should work.

let string = ["1","2","3","4","5"]

let newString = "\"[\"" + string.joined(separator: "\",\"") + "\"]\""

print(newString) // Prints "["1","2","3","4","5"]"

Edit: The best way is to use @vadian's answer. Albeit, this doesn't seem like a valid use case.

edited Sep 12, 2018 at 15:39

answered Sep 12, 2018 at 11:10

Rakesha Shastri

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21 Comments

Jhony Over a year ago

getting the same array ["1","2","3","4","5"]

Rakesha Shastri Over a year ago

@Jhony but as a single string. You want the string to enclose in double quotes as well?

Leo Dabus Over a year ago

This is an horrible hack you should tell OP to use the proper tools

Rakesha Shastri Over a year ago

@Jhony kindly remove the accepted mark and mark vadian's answer accepted. You just need to append quotes on both sides of that answer to get what you need. My answer is not wrong but not the way to solve your problem.

vadian Over a year ago

@RakeshaShastri The string printed with debugDescription is exactly the expected string in the question (except the necessary virtually added backslashes).

|

vadian · Accepted Answer · 2018-09-12 11:19:31Z

3

The result is a JSON string so use JSONEncoder

let array =  ["1","2","3","4","5"]
do {
    let data = try JSONEncoder().encode(array)
    let string = String(data: data, encoding: .utf8)!
    print(string.debugDescription) // "[\"1\",\"2\",\"3\",\"4\",\"5\"]"
} catch { print(error) }

edited Sep 12, 2018 at 11:19

answered Sep 12, 2018 at 11:12

vadian

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2 Comments

Jhony Over a year ago

getting ["1","2","3","4","5"] i want this array in quoted ""

vadian Over a year ago

It is in double quotes, believe me. See the edited answer.

Hardik Thakkar · Accepted Answer · 2018-09-12 11:25:15Z

1

Try this code for swift 4

 override func viewDidLoad() {
        super.viewDidLoad()

        let strArray = self.getString(array: ["1", "2", "3"])
        print(strArray)

        // Do any additional setup after loading the view, typically from a nib.
    }

    func getString(array : [String]) -> String {
        let stringArray = array.map{ String($0) }
        return stringArray.joined(separator: ",")
    }

answered Sep 12, 2018 at 11:25

Hardik Thakkar

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Comments

XmasRights · Accepted Answer · 2018-09-12 11:20:13Z

0

extension Array {

    var fancyString: String {
        let formatted = self.description.replacingOccurrences(of: " ", with: "")
        return "\"\(formatted)\""
    }
}

let array = ["1", "2", "3", "4", "5"]
print(array.fancyString) //"["1","2","3","4","5"]"

Note: this solution will work with Arrays of any type

let ints = [1, 1, 3, 5, 8]
print(ints.fancyString) // "[1,1,3,5,8]"

answered Sep 12, 2018 at 11:20

XmasRights

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Comments

Ajay saini · Accepted Answer · 2018-09-12 11:24:08Z

0

You can convert your array into CSV string using this.

let productIDArray = ["1","2","3","4","5"]
let productIDString = productIDArray.joined(separator: ",")

answered Sep 12, 2018 at 11:24

Ajay saini

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Comments

Jogendar Choudhary · Accepted Answer · 2018-09-12 11:25:39Z

0

If you want from ["1","2","3","4","5"] to "["1","2","3","4","5"]" then check

You can do this in simple way, Please try this

 let arr = ["1","2","3","4","5"]
 let str = "\"\(arr)\""

edited Sep 12, 2018 at 11:25

answered Sep 12, 2018 at 11:15

Jogendar Choudhary

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5 Comments

Rakesha Shastri Over a year ago

Unfortunately this introduces an extra space between the elements.

Jogendar Choudhary Over a year ago

@RakeshaShastri: Print this on console then show me.

Rakesha Shastri Over a year ago

I believe you can do that yourself.

Jogendar Choudhary Over a year ago

@RakeshaShastri Now check

Rakesha Shastri Over a year ago

facepalm sigh

Community · Accepted Answer · 2020-06-20 09:12:55Z

0

func objectToJSONString(dictionaryOrArray: Any) -> String? {
do {
    
    //Convert to Data
    let jsonData = try JSONSerialization.data(withJSONObject: dictionaryOrArray, options: JSONSerialization.WritingOptions.prettyPrinted)
    
    //Convert back to string. Usually only do this for debugging
    if let JSONString = String(data: jsonData, encoding: String.Encoding.utf8) {
        return JSONString
    }
    
} catch {
    print(error.localizedDescription)
}

return nil
}

Output will be

Edit for an exact answer

Declare a string extension for string

extension String {
var unescaped: String {
    let entities = ["\0": "\\0",
                    "\t": "\\t",
                    "\n": "\\n",
                    "\r": "\\r",
                    "\"": "\\\"",
                    "\'": "\\'",
                    ]
    
    return entities
        .reduce(self) { (string, entity) in
            string.replacingOccurrences(of: entity.value, with: entity.key)
        }
        .replacingOccurrences(of: "\\\\(?!\\\\)", with: "", options: .regularExpression)
        .replacingOccurrences(of: "\\\\", with: "\\")
}
}

Modified code will be

let array = ["1","2","3","4","5"]

let jsonString = objectToJSONString(dictionaryOrArray: array)

print(jsonString!.debugDescription) // this will print "[\"1\",\"2\",\"3\",\"4\",\"5\"]"

let result = jsonString!.debugDescription.unescaped

print(result)

So Output

Happy Coding :)

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Sep 12, 2018 at 11:29

iamVishal16

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5 Comments

Leo Dabus Over a year ago

This is what OP is looking for but he doesn’t know yet

iamVishal16 Over a year ago

I am not getting. OP?

Leo Dabus Over a year ago

Original poster

Leo Dabus Over a year ago

@vadian answer it is also correct for Swift 4 or later

iamVishal16 Over a year ago

oh! It depends on OP now.

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