PHP replace part of string with link based on pattern

Question

I would like to replace all words starting with 3ABC with an link including the found word. For example:

teststring 3ABCJOEDKLSZ2 teststring hello test

Output would be:

test string <a href='https://google.com/search/3ABCJOEDKLSZ2'>3ABCJOEDKLSZ2</a>  teststring hello test

The substring I am looking for is always starting with 3ABC everything after that is dynamic.

Standard counter question for such kind of request: what have you tried so far? — B001ᛦ
– B001ᛦ, Commented Sep 13, 2018 at 13:54
3ABC\S+ or 3ABC[a-zA-Z\D]+ I think would do it... or if 3abc also is valid make the + a *. Hard to tell where your preg_replace went wrong without the code — user3783243
– user3783243, Commented Sep 13, 2018 at 13:59

David · Accepted Answer · 2018-09-13 14:00:02Z

2

You can use php's preg_replace function to match 3ABC followed by 0 or more characters that is not whitespace and then use the match in your code:

$literal = "teststring 3ABCJOEDKLSZ2 teststring hello test";
$formatted = preg_replace("/3ABC\S*/", '<a href="https://google.com/search/\0">\0</a>', $literal);

echo $formatted;

Fiddle: Live Demo

answered Sep 13, 2018 at 14:00

David

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1 Comment

TTS Over a year ago

As simple as it looks, I couldn't find the right replace formule. Thank you very much.

patrick · Accepted Answer · 2018-09-13 14:11:19Z

0

<?php
function makeLink($string)
{
    $pattern='/^3ABC[\w\d]+$/';
    $url='https://google.com/search/';
    $result=preg_replace($pattern, $url.$string ,$string);
    return $result;
}
echo makeLink('3ABCHJDGIFD');
?>

Like this? http://php.net/manual/en/function.preg-replace.php

the pattern will match any digit or word character after 3ABC.

edited Sep 13, 2018 at 14:11

answered Sep 13, 2018 at 14:03

patrick

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