PHP Laravel Check if Array is empty

Question

I am struggling with displaying some content depending on if an array does have a value or not.Every time the code in the else part is executed. What's wrong here? Is there any syntax error with this code? I'm using php laravel.

foreach($now as $v)
{
        $arry[$c++]=$v->Code; 
}
if($arry==null){
     Do Something
}
else{
     Do Something else
}

you should check array's length rather than comparing with null — Jigar Shah
– Jigar Shah, Commented Sep 14, 2018 at 8:20
check for empty? Sounds like a duplicate of stackoverflow.com/questions/2216052/… — Lars Mertens
– Lars Mertens, Commented Sep 14, 2018 at 8:21
if you want to check that array is empty you should use empty($arry) or $arry === [] construction — Artem Ilchenko
– Artem Ilchenko, Commented Sep 14, 2018 at 8:21
Possible duplicate of How to check whether an array is empty using PHP? — Jigar Shah
– Jigar Shah, Commented Sep 14, 2018 at 8:25

Yasin Arafat · Accepted Answer · 2018-09-14 08:30:07Z

8

if($arry) {
     echo 'The array is not empty';
}
else {
     echo 'The array is empty';
}

For more: How can you check if an array is empty?

edited Sep 14, 2018 at 8:30

answered Sep 14, 2018 at 8:21

Yasin Arafat

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Comments

Aleksandrs · Accepted Answer · 2018-09-14 09:14:51Z

3

Better to do if (!empty($arry)) {}

P.S. yes if (!$arry) do the same, but every person which is not familiar with php or even have little understanding of programming, should understand the code. Whats mean "not array", but if it will be "not empty array" is more clear. It is very straight forward.

Clean code

edited Sep 14, 2018 at 9:14

answered Sep 14, 2018 at 8:23

Aleksandrs

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Comments

Max · Accepted Answer · 2021-02-19 09:50:57Z

2

if ( sizeof($arry) ) { // If more than 0
   // Do Something
} else { // If 0
   // Do Something else
}

edited Feb 19, 2021 at 9:50

Max

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answered Sep 14, 2018 at 8:23

Manoj Negi

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1 Comment

Marcin Orlowski Over a year ago

Note that in PHP sizeof() is NOT what you may think it is based on your experience from i.e. C. It's just alias for count(). Luckily, since IIRC PHP5 array counter is maintained internally, but prior that change it was really iterating over all the elements counting. So beware underlying implementation. Also this code is showing the intent. You do not care how many elements you have. You want to know it is not empty, so you should have written if (!empty($arry)) {... not empty....} else { .... }

vivek kumar · Accepted Answer · 2024-06-29 18:58:50Z

1

 if(!$users->isEmpty()){
        return response()->json(['status' => 1, 'data' => $users]);
    }else{
        return response()->json(['status' => 0, 'msg' => 'no employees found']);
    }

answered Jun 29, 2024 at 18:58

vivek kumar

111 bronze badge

Comments

Raghbendra Nayak · Accepted Answer · 2018-09-14 08:32:24Z

0

Always check array before iterate in foreach and check with count function to check its value

if(isset($now) && count($now)>0){
    foreach($now as $v) {
            $arry[$c++]=$v->Code; 
    }
}
if(count($arry)>0){
     Do Something
}
else{
     Do Something else
}

answered Sep 14, 2018 at 8:32

Raghbendra Nayak

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Comments

Jay Teli · Accepted Answer · 2018-09-14 10:19:11Z

-1

You can use empty() or count() or sizeof() as below :

$a = [];
if(empty($a)) {
    echo 'empty' . PHP_EOL;
} else {
    echo '!empty' . PHP_EOL;
}
if(count($a) == 0) {
    echo 'empty' . PHP_EOL;
} else {
    echo '!empty' . PHP_EOL;
}
if(sizeof($a) == 0) {
    echo 'empty' . PHP_EOL;
} else {
    echo '!empty' . PHP_EOL;
}

echo empty($a) . PHP_EOL; // 1
echo count($a) . PHP_EOL; // 0
echo sizeof($a) . PHP_EOL; // 0

Output : 
empty
empty
empty
1
0
0

answered Sep 14, 2018 at 10:19

Jay Teli

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Comments

Nisfan · Accepted Answer · 2018-09-14 08:32:32Z

-2

this is not related to Laravel framework

if (count($arry) > 0) 
   Do Something
else
   Do Something else

edited Sep 14, 2018 at 8:32

answered Sep 14, 2018 at 8:22

Nisfan

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