a = "This is some text"
b = "This text"
I want to compare the variable b in a and should return true even if the text contains more than two words like
a = "This is another text here"
b = "This another here"
even if I compare b in a should return true in python
Condition: True == All words in b found, the same order, in a.
In the above examples, the words have to be in the same order and upper/lowercase.
a = "This is some text"
b = "This text"
c = 0
for i in b.split(): # check for each word in a
if i in a: c = c + 1 # if found increases the count
c>=2 # true
or
len([value for value in a.split() if value in a.split()]) >= 2
You can mimic the behavior to a certain extent using regex.
import re
def is_like(text,pattern):
if '%' in pattern:
pattern = pattern.replace('%','.*?')
if re.match(pattern,text):
return True
return False
a = "This is another text here"
b = "This%another%here"
print(is_like(a,b))
>>>>True
a = "Thisis sometext"
b = "This % text"
print(is_like(a,b))
>>>>False
a = "Thisis sometext"
b = "This%text"
print(is_like(a,b))
>>>>True
a = "This is some text"
b = "This text"
print(is_like(a,b))
>>>>False
Note that I have not implemented any escaping for % character, so searching for % won't work.
