Compare three array in JavaScript

Question

Here is my code

const obj1 = [{ext: '1287',ip: '(Unspecified)',queue: []}];
const obj2 = [{Queue: '222',Members: [{"ext":"1287"},{"ext":"4118"}],Callers: []},{Queue: '111',Members: [{"ext":"4131"},{"ext":"1287"},{"ext":"4138"}],Callers: []}];

const hasExt = ext => o2 => o2.Members.some(m => m.ext === ext)

const result = obj1.map(o1 => {
  const newQueue = obj2
    .filter(hasExt(o1.ext))
    .map(m => m.Queue);

  return { ...o1, queue: [...o1.queue, ...newQueue] };
})

console.log(result);

Here is my js fiddle https://jsfiddle.net/pravinnavle/myzsvbLr/1/ In the above part I'm comparing obj1 and obj2. If the value of ext key from obj1 matches the ext key of nested Members array of obj2 then the value of Queue key of obj2 get's pushed to a queue array in obj1. The output is as follow:

[
  {
    "ext": "1287",
    "ip": "(Unspecified)",
    "queue": [
      "222",
      "111"
    ]
  }
]

Now I have a third array obj3 like this

const obj3 = [{ ext: '1287',Prio: '1',State: 'Up'},{ ext: '1184',Prio: '1',State: 'Down'}]

I want to compare obj1 and obj3. If the value of ext key from obj1 matches the value of ext key in obj3 then the Prio and State keys of obj3 should be pushed to a calls array in obj1 and the final array should be like as shown below.

[
  {
    "ext": "1287",
    "ip": "(Unspecified)",
    "queue": [
      "222",
      "111"
    ],
    "calls": [
      {
      "Prio" : 1,
      "State" : "Up",
      }
    ],
  }
]

I'm having trouble to compare obj1 with obj3 and output it in the result constant that is present in the code at the beginning. How do I do that?

your object are arrays it not an object

Amit Wagner
– Amit Wagner

2018-09-17 07:40:24 +00:00
Commented Sep 17, 2018 at 7:40 — Amit Wagner
– Amit Wagner, Commented Sep 17, 2018 at 7:40
ok. I edited the question

node_man
– node_man

2018-09-17 07:43:04 +00:00
Commented Sep 17, 2018 at 7:43 — node_man
– node_man, Commented Sep 17, 2018 at 7:43

Alex G · Accepted Answer · 2018-09-17 07:55:39Z

1

You can try something like that.

const obj2 = [{
        "ext": "1287",
        "ip": "(Unspecified)",
        "queue": [
            "222",
            "111"
        ]
    }
];

const obj3 = [{ ext: '1287',Prio: '1',State: 'Up'},{ ext: '1184',Prio: '1',State: 'Down'}];

const func = (obj1, obj2) => {
    obj1.forEach((a) =>
      obj2.forEach((b) => {
        if (b.ext === a.ext) a.calls = (a.calls || []).concat(Object.assign({}, { Prio: b.Prio, State: b.State }));
      })
    );
};

func(obj2, obj3);

console.log(obj2);

answered Sep 17, 2018 at 7:55

Alex G

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2 Comments

node_man Over a year ago

Thanks Alex. I implemented your logic and it worked for me.

node_man Over a year ago

can you help me with this

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