I'm using jqPlot and I need to turn this JSON which I receive from a WCF service:
[{ "x": 2, "y": 3 }, { "x": 25, "y": 34 }]
into this array or arrays:
[[2,3],[25,34]]
I've tried JSON.parse & eval but to no avail.
thanks
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2 Answers
You can use $.map() to do that:
var data = [{ "x": 2, "y": 3 }, { "x": 25, "y": 34 }]
var flattenedResult = $.map(data, function(point) {
return [[ point.x, point.y ]];
});
5 Comments
Guffa
The
map method flattens the result, so flattenedResult will contain [2,3,25,34], not [[2,3],[25,34]]. Also, you forgot the step of parsing the JSON.
Jamie Carruthers
Wow Mr. Encosia answered my question. This must be how normal people feel when they meet a celebrity...
Dave Ward
@Guffa: You're right. Wrapping the return array in a second array literal defeats the flattening though. If he's requesting it with jQuery, the JSON should already parsed by the time he gets it, so no need for that.
Dave Ward
@Jamie: I'm definitely sure that I'm nothing like a celebrity.
Guffa
@Dave Ward: Wrapping the return array in a second array would give the result
[[2,3,25,34]], not [[2,3],[25,34]].Parse the string into an array of objects:
var json = '[{ "x": 2, "y": 3 }, { "x": 25, "y": 34 }]';
var o = $.parseJSON(json);
Then replace each object in the array with an array:
for (var i=0; i<o.length; i++) o[i] = [o[i].x, o[i].y];
2 Comments
Jamie Carruthers
This actually work's very nicely, whereas the other answers result in a flattened array.
Guffa
@Jamie Carruthers: Yes, I tested the code before posting it. :) I first tried the
map method, but as I noticed that it flattens the result I went with a regular loop instead.