(I am new to coding) I am trying to replace an array element with itself plus 1, but it does not seem to work. In the following I am trying to replace the 3rd element:
int l=5;
int histogram[l];
histogram[l]={0};
histogram[2] = histogram[2] + 1;
It gives me the following error;
Expected ';' after expression
histogram
First of all @Elias, you have defined the size of array histogram to be 5. And are initializing histogram[5] to 0. But the last index of any array is size-1...(size minus one), since the array index starts at zero instead of one.
And secondly, you need to initialize the entire histogram[] array from histogram[0] to histogram[4] before you can do any arithmetic operations like adding or subtracting them. In your code fragment, you are trying increment histogram[2] by one even before it it initialized to any value.
so try this...
int len = 5, i = 0;
int histogram[len];
for(i = 0; i < len; i++) {
histogram[i] = 0;
}
histogram[2] = histogram[2] + 1; //can also use histogram[2] += 1; or histogram[2]++;
int histogram[len] = {0};?int histogram[l]; is not C++, it's a gcc extension.
histogram[l]={0}; is undefined behaviour, you are accessing past the end of your array. There is no way of assigning all the elements of a C-style array. You seem to be confusing that with the syntax to initialise histogram, which is only applicable in the declaration.
Modern C++ shuns C-style arrays. If you want a constant size, use
std::array<int, 5> histogram = {};
or if you want a size based on a runtime variable, use
std::vector<int> histogram(l, 0);
histrogram? Where is this line?histogramis, you could dohistogram[2] += 1orhistogram[2]++or++histogram[2].int histogram[5] = {0};. Usingl(a variable not known at compile time) for the size is not supported by the C++ standard and the 3rd line is just odd, you try to assign an array to an integer, mind you it's outside of your array too. In general though, using avectorwould be best.las a variable name, because it can easily be misinterpreted as the number1.