Nested Function in a Class, Python

Question

I am trying to have Nested function inside a class. Here is my code

class big():
        def __init__(self):
        self.mas = "hello"
    
    def update(self):
        
        def output(self):
            print(self.mas)
        
        self.output()
        
thing = big()

thing.update()

However when it runs I get an error that output is not defined. How can i run the output function inside the update function?

Mikhail Burshteyn · Accepted Answer · 2018-09-20 06:19:31Z

3

Just call it as output(), without self. The way you've defined it, it basically is a local variable inside your update method, not an attribute of the class.

class big():
    def __init__(self):
        self.mas = "hello"

    def update(self):
        def output():
            print(self.mas)

        output()

thing = big()

thing.update()

edited Sep 20, 2018 at 6:19

answered Sep 19, 2018 at 20:28

Mikhail Burshteyn

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2 Comments

Reblochon Masque Over a year ago

You should probably not have self as arg to output, but if you do, you should pass it with the call. As it stands, it raises TypeError: output() missing 1 required positional argument: 'self'

Mikhail Burshteyn Over a year ago

@ReblochonMasque My mistake, fixed it

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