PHP declaring object as array for function parameter [duplicate]

Question

I'm quite new with PHP. I'm having problems declaring an object as array for function parameter. In Java, I simply use public void methodName (List<Object> listVariableName){} for passing a list of many Objects.

I did some research in PHP and one of the answers suggested to put array in method parameter declaration like so function myFunction($a, array Object $obj){}

Currently, I have a class named Lesson

class Lesson implements JsonSerializable{
private $lessonId;
    private $lessonNo;
    private $lessonTitle;
    private $isLessonActive;
    private $isLessonRemoved;

    //getters and setter here....
}

Then I'm trying to declare a method called addTopicLesson

function addTopicLesson(Topic $topic, array Lesson $lesson){

}

But, I'm getting an error in array Lesson $lesson

There's 1 topic and MANY lessons. How can I go about implementing or defining the method signature?

I found this but I'd like to know if there's a better approach than to call itself.

I'd appreciate any suggestion.

Thank you.

You can't type hint array of Objects, either array or Object — u_mulder
– u_mulder, Commented Sep 22, 2018 at 13:40

Jakub Matczak · Accepted Answer · 2018-09-22 13:42:11Z

1

List<T> is not an array. It's a list utilizing generic type mechanism.

There are no generics in PHP. You can only typehint an array but you cannot control what's inside it at the level of method declaration.

answered Sep 22, 2018 at 13:42

Jakub Matczak

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Comments

Rook · Accepted Answer · 2018-09-22 17:16:41Z

0

function addTopicLesson(Topic $topic,array $lessons)
{
  foreach($lessons as $lesson) 
  {
    addLesson($page);
  }
}

function addLesson(Lesson $lesson)
{
}

edited Sep 22, 2018 at 17:16

Rook

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answered Sep 22, 2018 at 13:43

Osama

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1 Comment

Jakub Matczak Over a year ago

This way you can pass only one instance of Lesson object. It will refuse to take an array.

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