I've the below array of users:
$users = [
[name => 'Alice', age => 22],
[name => 'Bob', age => 23],
[name => 'Charlie', age => 19]
];
I'd like to create an array of users that are at least 20 years old. I tried:
$allowed_users = array_filter($users, function($user) {
return $user->age >= 20;
});
var_dump($allowed_users);
Which returns an empty array. I suppose I'm doing something wrong with the callback function.
You are using object notation with an array. It's a simple fix:
$users = [
['name' => 'Alice', 'age' => 22],
['name' => 'Bob', 'age' => 23],
['name' => 'Charlie', 'age' => 19]
];
$allowed_users = array_filter($users, function($user) {
return $user['age'] >= 20;
});
var_dump($allowed_users);
And although it's not an error in itself, use quotes in your keys, otherwise the interpreter will throw a notice.
You need to access your array members in array syntax, you are using object syntax.
<?php
$users = [
['name' => 'Alice', 'age' => 22],
['name' => 'Bob', 'age' => 23],
['name' => 'Charlie', 'age' => 19]
];
$allowed_users = array_filter($users, function($user) {
return ($user['age'] >= 20);
});
var_dump($allowed_users);
Firstly the key of each sub user array is not wrap in double quote or single quote
$users = [
['name' => 'Alice', 'age' => 22],
['name' => 'Bob', 'age' => 23],
['name' => 'Charlie', 'age' => 19]
];
and you must access each sub array key using the key in bracket $users[1]['name'] return the name of the first user which is in the first sub array
$allowed_users = array_filter($users, function($user) {
return $user['age'] >= 20;
});
You can use following Code:
function onStart(){
$users = [
['name' => 'Alice', 'age' => 22],
['name' => 'Bob', 'age' => 23],
['name' => 'Charlie', 'age' => 19]
];
$allowed_users = array_filter($users, function($user) {
return $user['age'] >= 20;
});
var_dump($allowed_users);
}
