mcve :
d1 = {"a":1}
d2 = {"b":2}
import json
with open('test2.json','w+') as file:
for d in [d1,d2]:
json.dump(d,file)
test2.json content :
{"a": 1}{"b": 2}
Desired Result :
[{"a": 1},{"b": 2}]
How can I achieve it?
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6 Answers
d1 = {"a":1}
d2 = {"b":2}
import json
array = [json.dumps(d) for d in [d1,d2]]
Then write array to file
Comments
Create a list instead, and dump that list directly.
with open('test2.json','w+') as file:
d = [d1, d2]
json.dump(d,file)
1 Comment
Bal Krishna Jha
This is not possible as in actual example in each iteration json object is being generated. So maybe I've to add those json in list and then finally dump those.
try this
d1 = {"a":1}
d2 = {"b":2}
import json
tab = [d1, d2]
with open('test2.json','w+') as file:
json.dump(tab ,file)
Comments
Use list and append both the dictionary into list and then write list into the file.
d1 = {"a":1}
d2 = {"b":2}
import json
with open('test2.json','w+') as file:
for d in [d1,d2]:
list1 = []
list1.append(d1)
list1.append(d2)
json.dump(list1,file)
Comments
Try this
d1 = {"a":1}
d2 = {"b":2}
import json
with open('test2.json','w+') as file:
json.dump([d1,d2],file)
Comments
A list of dictionaries is a json serializable ofject already, so just serialize the whole object you need:
import json
with open('test2.json','w+') as file:
json.dump([{"a":1}, {"b":2}],file)
