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I have a file that contain list of users and his token value like :

- name: A@X/xxxxxx:123
  user:
    token: abcdefghijk
- name: B@Y/yyyyyyy:456
  user:
    token: dassafsdfscczcz

I want to get token value for specific name using bash script ?

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  • 2
    Is this a YAML file? Don't parse it with non-syntax aware tools. Commented Sep 28, 2018 at 9:03
  • i edited the post , i need to get token value for specific name Commented Sep 28, 2018 at 9:07
  • Install a proper YAML parser - github.com/0k/shyaml Commented Sep 28, 2018 at 9:17
  • Is there is bash Script ? Commented Sep 28, 2018 at 9:20

2 Answers 2

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$ param="A@X"
$ awk '{if($2~/name/) {a=$3} else {print a,$0}}' temp |grep token|grep $param|awk '{print $3}'
abcdefghijk
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1

You can use grep:

grep -A 2 "A@X/xxxxxx:123" THEDATAFILE | grep token | cut -d':' -f2

It will work even if you have the same user twice and print both tokens.

Tested with GNU grep on Linux.

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